answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mash
21 hour ago
11

A 3.50-meter length of wire with a cross-sectional area of 3.14 × 10-6 meter2 is at 20° Celsius. If the wire has a resistance of

0.0625 ohms, what is its resistivity?
Physics
1 answer:
kicyunya [2.2K]20 hours ago
8 0

Answer:

5.6\times 10^{-8}\ Ohm.m

Explanation:

Resistivity can be calculated using \rho=\frac {AR}{L} where A stands for cross-sectional area, R for resistance, L for the length, and \rho for the resistivity constant. By substituting 0.0625 for R, 3.14 × 10-6 for A, and 3.5 m for L, the resulting resistivity is

\rho=\frac {3.14\times 10^{-6}\times 0.0625}{3.5}=5.60714285714285714285714285714285714285\times 10^{-8}\approx 5.6\times 10^{-8}\ Ohm.m

You might be interested in
9. A 2 liter bottle of Coke weighs about 2 kilograms. If that bottle were combined with an equal amount of anti-Coke, how many J
Maru [2355]

Answer:

The energy expected to be released is calculated to be 4182 Joules.

Explanation:

The total mass of coke is 2 kg, which is equivalent to 2000 g

1 calorie per gram corresponds to 4.184 Joules of energy

4.184 J/gC * 2000g results in 8368 J

1 food calorie approximates to 4186 J

By subtracting, we find 8368 - 4186

Hence, the total energy that will be released amounts to 4182 Joules.

3 0
6 days ago
In a third class lever, the distance from the effort to the fulcrum is ____________ the distance from the load/resistance to the
serg [2593]
The full sentence states:
In a third class lever, the distance between the effort and the fulcrum is LESS than the distance between the load/resistance and the fulcrum.
In a third class lever, the fulcrum is positioned on one end of the effort, while the load/resistance is on the opposite side, placing the effort somewhere in between. Consequently, the distance from the effort to the fulcrum is less than that from the load to the fulcrum.
4 0
2 days ago
Jack pulls a sled across a level field by exerting a force of 110 n at an angle of 30 with the ground. what are the parallel and
Softa [2029]
<span>A force of 110 N is applied at an angle of 30</span>°<span> to the horizontal. Because the force does not align directly either vertically or horizontally with the sled, it can be broken down into two components based on sine and cosine.

For the component parallel to the ground:
x = rcos</span>β
<span>x = 110cos30</span>°
<span>x = 95.26

For the component perpendicular to the ground:
y = rsin</span>β
<span>y = 110sin30</span>°
<span>y = 55</span>
3 0
27 days ago
Read 2 more answers
In an inertial frame of reference, a series of experiments is conducted. in each experiment, two or three forces are applied to
Yuliya22 [2420]
Objects will stay in a stationary position if the total force acting on them amounts to zero; this occurs when equal forces are applied in opposite directions. According to Newton's second law, if the net force on an object is zero, it will not move.
8 0
19 days ago
Compare the momentum of a 6,300-kg elephant walking 0.11 m/s and a 50-kg dolphin swimming 10.4 m/s. your answer
inna [2205]
<span>First, apply Newton's second law of motion: F = ma. Force equals mass times acceleration. This law describes force as the product of mass multiplied by acceleration (which is different from velocity). As acceleration is the variation in velocity over time, we have force = (mass * velocity) / time, leading us to conclude that (mass * velocity) / time will equal momentum / time. Hence, we derive the equation mass * velocity = momentum. Momentum = mass * velocity. For the elephant, with a mass of 6300 kg and velocity of 0.11 m/s, Momentum = 6300 * 0.11, resulting in P = 693 kg (m/s). For the dolphin, having a mass of 50 kg and moving at 10.4 m/s, Momentum = 50 * 10.4, yielding P = 520 kg (m/s). Thus, the elephant has a greater momentum (P) due to its larger size.</span>
5 0
1 month ago
Other questions:
  • An aluminum wire of length 1.0 meter has a resistance of 9.0x10^-3 ohm. If the wire were cut into two equal lengths, each length
    11·2 answers
  • a carpenter hits a nail with a hammer. compared to the magnitude of the force the hammer exerts on the nail, the magnitude of th
    8·2 answers
  • A Honda Civic travels in a straight line along a road. The car’s distance x from a stop sign is given as a function of time t by
    7·1 answer
  • A fox locates rodents under the snow by the slight sounds they make. The fox then leaps straight into the air and burrows its no
    10·1 answer
  • f a car is speeding down a road at 40 miles/hour (mph), how long is the stopping distance D40 compared to the stopping distance
    6·1 answer
  • The position of a particle is r⃗ (t)=(3.0t2iˆ+5.0jˆ−6.0tkˆ)m. (a) Determine its velocity and acceleration as functions of time.
    10·1 answer
  • Which process is a form of mechanical weathering?
    15·2 answers
  • A car covers 72 kilometers in the first hour of its journey. In the next hour, it covers 90 kilometers. What is the amount of wo
    14·1 answer
  • Driving down a quiet street on a summer day with the car windows down, you see a convertible approaching from the opposite direc
    12·1 answer
  • A rear window defroster consists of a long, flat wire bonded to the inside surface of the window. When current passes through th
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!