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mash
3 months ago
11

A 3.50-meter length of wire with a cross-sectional area of 3.14 × 10-6 meter2 is at 20° Celsius. If the wire has a resistance of

0.0625 ohms, what is its resistivity?
Physics
1 answer:
kicyunya [3.2K]3 months ago
8 0

Answer:

5.6\times 10^{-8}\ Ohm.m

Explanation:

Resistivity can be calculated using \rho=\frac {AR}{L} where A stands for cross-sectional area, R for resistance, L for the length, and \rho for the resistivity constant. By substituting 0.0625 for R, 3.14 × 10-6 for A, and 3.5 m for L, the resulting resistivity is

\rho=\frac {3.14\times 10^{-6}\times 0.0625}{3.5}=5.60714285714285714285714285714285714285\times 10^{-8}\approx 5.6\times 10^{-8}\ Ohm.m

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