Answer:
Explanation:
The equation used to determine the maximum height of the bowling pin during its trajectory is given by;
H = u²/2g
where u, the initial speed/velocity, equals 10m/s
g stands for gravitational acceleration = 9.81m/s²
Substituting in the values gives us
H = 10²/2(9.81)
H = 100/19.62
Consequently, the highest point of the bowling pin's center of mass is approximately 5.0m.
Response:
The horizontal span of Sosa is 276.526 ft or 84.28 meters.
Explanation:
As illustrated in the diagram, let point O denote Sosa's starting position. She travels 361 ft at a 50-degree angle relative to the horizontal.
sin 50 = 
0.7660 = h / 361
h = 276.526 ft
h = 84.28 meters
The horizontal distance of Sosa is 276.526 ft or 84.28 meters.
Answer:
The flow rate of water is (300000kg/s) = (300000l/s)
Explanation:
To compute the volume of moving fluid per second in the channel, we consider the channel's section, the water depth, and the fluid velocity:
Volume flow rate = 15m × 8m × (2.5m/s) = 300 m³/s
To find the mass or liters of water flowing per second, multiply the volume of circulating fluid by the water's density:
Flow rate of water = (300m³/s) × (1000kg/m³) = (300000kg/s) = (300000l/s)
It is important to note that 1kg of water is approximately equivalent to 1 liter.
Answer:
The outcome of adding 999mm to 100m is 101m.
Explanation:
That's my belief.
The calculation for the horizontal component is performed as follows:
Vhorizontal = V · cos(angle)
For your instance, Vhorizontal = 16 · cos(40) equates to 12.3 m/s
Conclusion: 12.3 m/s
