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WITCHER
1 month ago
13

A piece of a metal alloy with a mass of 114 g was placed into a graduated cylinder that contained 25.0 mL of water, raising the

water level to 42.5 mL. What is the density of the metal?
Physics
1 answer:
ValentinkaMS [3.4K]1 month ago
8 0

Answer:

6.51 g/c.c

Explanation:

Mass, m = 114 g

Initial volume, V1 = 25 mL

Final volume, V2 = 42.5 mL

The volume of the metal piece, V = V2 - V1 = 42.5 - 25 = 17.5 mL

1 mL = 1 c.c

Thus, the volume of metal is 17.5 c.c.

Let density of the metal be d.

Density = mass / volume

d = 114 / 17.5 = 6.51 g/c.c

Hence, the density of the metal is 6.51 g/c.c.

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A uniformly charged spherical droplet of mercury has electric potential Vbig throughout the droplet. The droplet then breaks int
kicyunya [3294]

Answer:

\frac{V_{big}}{V_{small}} = n^{2/3}

Explanation:

Let the charge on the large droplet be denoted as Q.

When the radius of the droplet is R, the electric potential for the larger droplet can be expressed as:

V_{big} = \frac{KQ}{R}

If it splits into n identical droplets, let the charge of each be "q" and their radius be "r".

Applying volume conservation gives us:

\frac{4}{3}\pi R^3 = n(\frac{4}{3}\pi r^3)

r = \frac{R}{n^{1/3}}

Now, the potential for the smaller droplets is given as:

V_{small} = \frac{kq}{r}

V_{small} = \frac{K(Q/n)}{\frac{R}{n^{1/3}}}

V_{small} = \frac{1}{n^{2/3}}\frac{KQ}{R}

\frac{V_{big}}{V_{small}} = n^{2/3}

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2 months ago
Considering the activity series given for nonmetals, what is the result of the below reaction? Use the activity series provided.
ValentinkaMS [3465]

Response: The result would be no reaction.

Clarification:

7 0
2 months ago
Read 2 more answers
In the past, salmon would swim more than 1130 km (700 mi) to spawn at the headwaters of the Salmon River in central Idaho. The t
Keith_Richards [3271]

Answer:

E_t_o_t_a_l=7.603MJ

Explanation:

The overall energy expenditure of the salmon, which corresponds to its swimming upstream effort, W, is linked to its specific mechanical power. Mechanical \ power calculated per unit mass can be derived from the following equation:

\frac{p}{m}=\frac{1}{m}|\frac{dW}{dt}|=2W/kg\\\frac{1}{2}|\frac{W}{22\times 24 \times 60\times 60}|=2\\\\W=7.603MJ

As a result, the total energy utilized during the 22-day journey is 7.603 MJ

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2 months ago
A small block of mass 200 g starts at rest at A, slides to B where its speed is vB=8.0m/s,vB=8.0m/s, then slides along the horiz
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Answer

Data provided:

mass of the block = 200 g = 0.2 Kg

Velocity at A = 0 m/s

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distance of slide = 10 m

height of the block = 4 m

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kinetic energy calculated as

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b) using the formula v² = u² + 2 a s

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