The house Trevor's family lives in has 666 people (including Trevor) and 333 bathrooms. In the past month, each person showered

Solution:

There are 4 ways.

Detailed explanation:

Candice has a total of 15 + 9 = 24 candies. Since she has three younger brothers, and 24 can be divided by 3 (24/3 = 8). Both 15 and 9 can also be divided by 3 (15/3 = 5 and 9/3 = 3).

- She can distribute 5 tootsie rolls to each brother.

- She can provide 3 twizzlers to each brother.

- She can give each brother 5 tootsie rolls and 3 twizzlers (if she decides to share all her candies).

- She can give them one of each type of candy, leaving her with 12 tootsie rolls and 6 twizzlers (this would be the best option if she wants to keep some for herself).

I see four methods to accomplish this, and two methods remain after her mother instructs her to share at least one of each candy type with all three brothers.

Answer:

A. Combining one pound of pistachios with one pound of almonds costs $20.

C. Decreasing the almond quantity by one pound leads to a total price of $40.

E. The price p (in dollars) per pound of pistachios is represented by the equation 2p + 3(p – 4) = 48.

Step-by-step explanation:

Let:

x = cost per pound of pistachios

y = cost per pound of almonds

We know that

x = y + 4 (Equation A)

2x + 3y = 48 (Equation B)

Substitute x from Equation A into Equation B:

2(y + 4) + 3y = 48

2y + 8 + 3y = 48

5y = 48 – 8

y = 8

Find x:

x = 8 + 4 = 12

Therefore, pistachios cost $12 per pound and almonds cost $8 per pound.

Verify the statements:

Case A) One pound of each equals $20.

True, since 12 + 8 = 20.

Case B) Pistachios cost twice as much as almonds.

False, because 2 × 8 = $16 ≠ $12.

Case C) Reducing almond pounds by 1 yields $40 total.

True, as 2(12) + 2(8) = 24 +16 = 40.

Case D) The almond cost modeled by 2(a – 4) + 3a = 48.

False; it should be 2(a + 4) + 3a = 48.

Case E) The pistachio cost modeled by 2p + 3(p – 4) = 48.

True, since p = a + 4 implies a = p – 4.

To calculate this, a specific formula will be necessary. Years = log (total/principal) / [n * log (1 + rate / n)]. Part A) For Calvin: $400 at 5% monthly results in $658.80; Time =? Monthly compounding, n = 12. Thus, Years = log(658.80/400) / [12 * log(1+ (.05/12))]. Subsequently, Years = log( 1.647) / (12 * log(1.0041666667)). Then, Years = 0.21669359917 / 12 * 0.0018058008777. Thus resulting in Years = 0.21669359917 / 0.0216696105. Ultimately, Years ≈ 9.999884362. Part B) For Makayla: $300 at 6% quarterly yields $613.04; Time=? Quarterly compounding, n = 4. Therefore, Years = log(613.04/300) / [4 * log (1 +.06/4)]. This results in Years = log(2.0434666667) / (4 * log(1.015)). Years thus equals 0.31036755784 / (4 * 0.0064660422492), resulting in Years ≈ 11.9999044949. The approximate difference is about 3 years.

Answer:

89

Step-by-step explanation:

Given that

2 O, 2 T and 1 M

Now based on this, the following arrangements exist  

1

Three arrangements i.e. {M,T,O}

2

XX or XY

XX in 2C1 = two arrangements i.e. {OO or TT}

XY in 3C2 × 2! = six arrangements

3

XXY or XYZ

XXY in 2C1 × 2C1 × 3! ÷ 2! = twelve arrangements

XYZ in 3C3 × 3! = six arrangements

4

XXYY or XXYZ

XXYY = 4! ÷ (2! × 2!) = six arrangements

XXYZ in 2C1 ×  4! ÷ 2! = twenty four arrangements

5

= 5! ÷ (2! ×2!)

= 120 ÷ 4

= 30

Thus, the overall total is

= 3 + (2 +6)+ (12 +6) + (6 +24) + 30

= 89