Answer: The frequency is 1714.3 Hz
Explanation: The calculation is derived from the Doppler effect formula.
Since the source is approaching the observer, the observer's velocity is considered positive.
Refer to the attached document for the detailed derivation
The ball was released from a height of 20 meters
Explanation:
The scenario is as follows:
1. A ball drops from the edge of a cliff.
2. Upon reaching the ground, the energy held in its gravitational potential energy transforms entirely into kinetic energy.
This implies K.E = P.E.
3. The ball impacts the ground at a speed of 20 m/s.
4. The gravitational field strength noted is 10 N/kg.
<pOur goal is to ascertain the height from which the ball was dropped.<pSince the ball was dropped from a cliff, its initial velocity is 0.<p→ K.E =where v is the final velocity, is the initial velocity, and m is the mass.
→ K.E =
→ K.E = 200 m joules when the ball strikes the ground.
<p→ P.E = mg hwhere g is the gravitational field strength, m is mass, and h signifies height.
<p→ g = 10 N/kg.<p→ P.E = m(10)(h)→ P.E = 10m h joules.
<p→ P.E = K.E.→ 10m h = 200 m.
Dividing through by 10m yields:
→ h = 20 meters.
The ball was released from a height of 20 meters.
Learn more
To understand more about gravitational potential energy, visit
Answer:
Explanation:
We define the linear charge density as:
Where L is the length of the rod, in this scenario the semicircle's length is L = πr
The potential at the center created by a differential element of charge is:
where k denotes Coulomb's constant
r signifies the distance from dq to the center of the circle
Thus.
The potential at the semicircle's center
Explanation:
The formula for the electric field produced by an infinite sheet of charge is outlined below.
E =
where, is the surface charge density
Following this, the formula for the electric force acting on a proton is given as:
F = eE
where, e is the charge of a proton
According to Newton's second law of motion, the overall force on the proton can be expressed as follows.
F = ma
a =
=
=
According to kinematic equations, the proton's speed in the perpendicular direction can be described as follows.
=
=
= 683.974 m/s
Thus, the overall speed of the proton can be calculated as follows.
v' =
=
= 1178.73 m/s
Consequently, we conclude that the proton's speed is 1178.73 m/s.