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Svetlanka
11 days ago
10

Andrea and Chuck are riding on a merry-go-round. Andrea rides on a horse at the outer rim of the circular platform, twice as far

from the center of the circular platform as Chuck, who rides on an inner horse. When the merry-go-round is rotating at a constant angular speed, Andrea's tangential speed is which of the following? a) twice Chuck's b) the same as Chuck's c) half of Chuck's d) impossible to determine B. When the merry go round is rotating at a constant angular speed, Andrea's tangential speed is a) twice Chuck's b) the same as Chuck's
Physics
1 answer:
Ostrovityanka [3.2K]11 days ago
5 0

Response: a) Andrea's speed is double that of Chuck's

Rationale:

Assuming constant angular speed and the merry-go-round behaving as a rigid body, the separation between points remains unchanged, so the points situated further from the center must travel at higher speeds compared to those nearer to it.

There is a connection between tangential speed and angular speed, as illustrated by the following equations, which define linear and angular speed in relation to the angle:

angle = arc / radius ⇒ Δθ/Δt = Δs/Δt / r ⇒ ω = v/r ⇒ v = ω. r

Provided that ω remains constant, v is proportionate to r, or the distance from the center (radius on the circular platform). Thus, if Andrea's radius is twice that of Chuck’s, her tangential speed must be twice that of Chuck's.

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