answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ahrayia
5 days ago
7

A trolley of mass 200kg is travelling north at 2m\s. It collides head on with a second trolley of mass 500kg which is travelling

south with a velocity of 5 m\s and they remain coupled together.
a)calculate the velocity of the two trolleys after collision.
b)what is the direction of motion of the trolley after collison?
Physics
1 answer:
Ostrovityanka [3K]5 days ago
6 0
200*2N+500*5S=(700)V
<span>400N-2500N=700V </span>
<span>determine V. A negative N indicates S</span>
You might be interested in
"a very light ideal spring stretches by 21.0 cm when it is used to hang a 135-n object. what is the weight of a piece of electro
Keith_Richards [3138]
In the first case, once equilibrium is established,
mg = kx
135 = k(0.21) [Converted to SI units]
k = 135/(0.21)

In the second case, similarly when reaching equilibrium,
mg = kx
mg = [(135)(.449)]/(0.21)
mg = weight of the electronic equipment = approximately 289 N.
6 0
1 month ago
Read 2 more answers
A 68 kg hiker walks at 5.0 km/h up a 9% slope. The indicated incline is the ratio of the vertical distance and the horizontal di
Softa [2918]

The formula used to calculate power is:

Power = Work / Time

Where Work is defined as Force multiplied by Distance, hence:

Power = Force * Distance / Time

This can also be expressed as:

Power = Force * Velocity<span>


Converting the velocity from km/h to m/s:</span>

Velocity = (5 km / h) (1000 m / km) (1 h / 3600 s)<span>
Velocity = 1.39 m/s 

</span>

The calculated force corresponds to the vertical component of the hiker's weight:

Force = Wy * g = W * sin θ * g

 

To find the angle θ, we utilize the slope, which is defined as:

slope = tan θ = ratio of vertical to horizontal distance

tan θ = 0.09

θ = 5.14˚

Thus, we have Force = 68 kg * sin(5.14˚) * 9.8 m/s²<span>
Force = 666.4 * sin(5.14) = 59.73 N 

</span>

<span>Now, let's compute the power:
<span>Power = 59.73 N * 1.39 m/s = 82.96 W
Given the hiker's efficiency is at 25%, we can find the metabolic power: 
<span>Metabolic Power = 82.96 W / 0.25 = 331.83 watts </span></span></span>
6 0
1 month ago
Your school science club has devised a special event for homecoming. You've attached a rocket to the rear of a small car that ha
inna [2965]

La force agissant pendant 9 s et la décélération pendant 12 - 9 = 3 s.

Distance totale parcourue = 990 m

vitesse initiale u = 0

Distance parcourue pendant l'accélération

s₁ = 1/2 a 9² où a est l'accélération

= 40.5 a

vitesse finale après 9 s

v = at = 9a

pendant la décélération

v² = u² - 5 x s₂

0 = (9a)² - 5 s₂

s₂ = 16.2 a²

Distance parcourue pendant la décélération = 16.2 a²

s₁ + s₂ = 990

40.5 a + 16.2 a² = 990

16.2 a² + 40.5 a - 990 = 0

a = 6.5

4 0
10 days ago
A new roller coaster contains a loop-the-loop in which the car and rider are completely upside down. If the radius of the loop i
Sav [3035]

Respuesta:

11.4 m/s

Explicación:

La fórmula para la aceleración centrípeta es:

a=\frac{v^2}{R}

donde, a es la aceleración, v la velocidad alrededor de la circunferencia y R el radio del círculo.

En este problema,

a = g = aceleración debida a la gravedad en la cima = 9.81\ m/s^2

v = ?

R = 13.2 m

Por lo tanto,

9.81=\frac{v^2}{13.2}

v^2=9.81\times {13.2}

v = 11.4 m/s

8 0
1 month ago
Two planets having equal masses are in circular orbit around a star. Planet A has a smaller orbital radius than planet B. Which
serg [3462]

Answer:

Explanation:

To approach this problem, we need to understand two key concepts.

First, the gravitational force on an object in orbit equals its mass multiplied by centripetal acceleration.

Secondly, Newton's law of universal gravitation defines the force between two masses: Fg = mMG/r², where Fg denotes gravitational force, m and M signify the masses, G represents the gravitational constant, and r indicates the distance separating the two masses.

Thus:

Fg = m v²/r

mMG/r² = m v²/r

v² = MG/r

Potential energy for each planet is expressed as:

PE = mgr = m (MG/r²) r = mMG/r

Kinetic energy for each planet is computed as:

KE = 1/2 mv² = 1/2 m (MG/r) = 1/2 mMG/r

Total mechanical energy is calculated as:

ME = PE + KE = 3/2 mMG/r

Since both planets share the same mass, the only variable is their orbital radius. Consequently, Planet A, with a smaller radius, possesses greater potential, kinetic, and mechanical energy.

6 0
1 month ago
Other questions:
  • Two students walk in the same direction along a straight path, at a constant speed one at 0.90 m/s and the other at 1.90 m/s. a.
    12·1 answer
  • Suggest reasons why poaching for subsistence is likely to be less damaging to the biodiversity of an area than poaching for prof
    9·1 answer
  • Smoking increases ____ levels in the blood, thus increasing the possibility of unwanted clotting.
    14·1 answer
  • A clock has an hour hand of length 2.4 cm and a minute hand of length 3.8 cm. (a) Calculate the position and velocity of the hou
    15·1 answer
  • Daring Darless wishes to cross the Grand Canyon of the Snake River by being shot from a cannon. She wishes to be launched at 65
    14·1 answer
  • A particle with mass 1.81×10−3 kg and a charge of 1.22×10−8 C has, at a given instant, a velocity v⃗ =(3.00×104m/s)j^. What are
    6·2 answers
  • A constant-velocity horizontal water jet from a stationary nozzle impinges normally on a vertical flat plate that rides on a nea
    10·1 answer
  • A 0.5 kg cheeseburger is lobbed at a particularly unhappy customer with a force of 10 N. While it is being thrown, what is the a
    5·1 answer
  • A strip 1.2 mm wide is moving at a speed of 25 cm/s through a uniform magnetic field of 5.6 t. what is the maximum hall voltage
    11·1 answer
  • Question #2
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!