Answer:
the lump descends
Explanation:
The full articulation of the query is
Upon fully submerging a 3 kg lump of material in a certain fluid, the fluid that would have occupied the space now filled by the lump weighs 2 kg. (a) When released, does the lump float up, sink, or remain steady
(a)
= Buoyant force acting upward on the lump
= mass of irregular lump = 3 kg
= mass of fluid displaced = 2 kg
The upward buoyant force on the lump is given by the weight of the displaced fluid, thus
the weight of the irregular lump of material is represented as
Given that the weight of the lump downward exceeds the upward buoyant force, the lump will indeed descend
Answer:
The rate at which the root beer level is decreasing is 0.08603 cm/s.
Explanation:
The formula for the volume of the cone is:
Where V denotes the cone's volume
r indicates the radius
h signifies the height
The ratio of radius to height remains consistent throughout the cone.
Thus, we have r = d / 2 = 10 / 2 cm = 5 cm
h is 13 cm
Consequently, r / h = 5 / 13
r = {5 / 13} h
Additionally, we differentiate the volume expression in relation to time:
Given that 
= -4 cm³/sec (the negative sign indicates outflow)
h equals 10 cm
Hence,
The rate at which the root beer level is decreasing is 0.08603 cm/s.
The tension exerted in the cable amounts to T = 16653.32 N.
Parameters:
Cross section area A = 1.3 m²
Drag coefficient CD = 1.2
Velocity V = 4.3 m/s
The angle formed by the cable with the horizontal is 30 degrees.
Density defined as follows:
The drag force FD is determined by the equation:
FD = (1/2) * ρ * V² * A * CD
Calculating the drag force yields 14422.2 N acting opposite to motion.
Given the cable's angle of 30 degrees with horizontal, the horizontal component contributes to the drag force calculation:
T * cos(30) = F_D
Thus, T = 16653.32 N.
Answer:
The convergence of light rays redirects them toward the focal point, resulting in a magnifying effect.
Explanation:
