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Nookie1986
28 days ago
7

0.036549 round to three sig figs

Chemistry
2 answers:
Alekssandra [2.7K]28 days ago
6 0
3 first significant figure
6 second significant figure
5 third significant figure
4 cannot exceed 5, so retain 5 instead of increasing it to 6

0.0365
Tems11 [2.4K]28 days ago
6 0

Answer:

0.0365

Explanation:

For the number given,

0.036549,

there are a total of 5 significant figures (i.e. 3, 6, 5, 4, and 9).

When rounding a decimal to 3 significant figures, we consider the fourth significant figure after the decimal point.

If that figure is 5 or greater, we increase the last significant figure by one, otherwise, it remains unchanged.

In this case, the fourth significant figure after the decimal point is 4.

Thus, 0.036549 ≈ 0.0365 (rounded to 3 significant figures)

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Now that Snape and Dumbledore has taught you the finer points of hydration calculations they have a slightly more challenging pr
eduard [2509]

Answer:

The integer value of x in the hydrate is 10.

Explanation:

Molarity=\frac{Moles}{Volume(L)}

Molar concentration of the solution = 0.0366 M

Volume of the solution = 5.00 L

Moles of hydrated sodium carbonate = n

0.0366 M=\frac{n}{5.00 L}

n=0.0366 M\times 5 mol=0.183 mol

Weight of hydrated sodium carbonate = n = 52.2 g

Molar mass of hydrated sodium carbonate = 106 g/mol + x * 18 g/mol

n=\frac{\text{mass of Compound}}{\text{molar mass of compound}}

0.183 mol=\frac{52.2 g}{106 g/mol+x\times 18 g/mol}

106 g/mol+x\times 18 g/mol=\frac{52.2 g}{0.183 mol}

By solving for x, we arrive at:

x = 9.95, approximating to 10

The integer x in the hydrate equals 10.

6 0
1 month ago
A compound composed of only carbon and chlorine is 85.5% chlorine by mass. propose a lewis structure for the lightest of the pos
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The visual representation is displayed in the following image.

For calculations, consider 100 grams of the compound:

ω(Cl) = 85.5% ÷ 100%.

ω(Cl) = 0.855; signifying the mass percentage of chlorine in the compound.

m(Cl) = 0.855 · 100 g.

m(Cl) = 85.5 g; this represents the mass of chlorine.

m(C) = 100 g - 85.5 g.

m(C) = 14.5 g; indicating the mass of carbon.

n(Cl) = m(Cl) ÷ M(Cl).

n(Cl) = 85.5 g ÷ 35.45 g/mol.

n(Cl) = 2.41 mol; this is the quantity of chlorine.

n(C) = 14.5 g ÷ 12 g/mol.

n(C) = 1.21 mol; this is the quantity of carbon.

n(Cl): n(C) = 2.41 mol: 1.21 mol = 2: 1.

The compound in question is identified as dichlorocarbene CCl₂.

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1 month ago
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I think the right choice is C. Coal, as it's utilized in making a multitude of products across the globe. I trust this information is useful to you.:)
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1 month ago
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The recommended daily allowance (rda of calcium is 1.2 g. calcium carbonate contains 12.0% calcium by mass. how many grams of ca
eduard [2509]
1) Calcium carbonate comprises 40.0% calcium by weight.
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2) The mass fraction mentioned is superfluous information.

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29 days ago
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Find the age ttt of a sample, if the total mass of carbon in the sample is mcmcm_c, the activity of the sample is AAA, the curre
castortr0y [2743]

Answer:

Explanation:

In a desert cave, an artifact has been discovered. The anthropologists investigating this artifact want to determine its age. They note that the current activity level of the artifact is 9.25 decays/s, and the carbon mass present is 0.100 kg. To ascertain the artifact's age, they will employ specific constants:

r=1.2

The formula for carbon 14 activity is

A=A_0e^{\lambda t}

where,

A_0 is the initial activity of the substance

Now, solve for t

-\lambda t=In\frac{A}{A_0}

t=-\frac{1}{\lambda} In(\frac{A}{A_0} )

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since,

A_0=\lambda r(\frac{m_c}{m_a} )

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Thus, the age of the artifact is

=-\frac{1}{\lambda} In(\frac{A\ m_a}{\lambda r m_c} )

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to two significant figures = 6300 years

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1 month ago
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