(a) The mass density of a gaseous compound was found to be 1.23 kg m^−3 at 330 K and 20 kPa. What is the molar mass of the compo
1 answer:
Answer:
La masa molar del compuesto es: 168.82 g/mol
La masa molar del gas es: 16.38 g/mol
Explanation:
(a)
Utilizando la ecuación de gases ideales:
donde,
P es la presión
V es el volumen
n es el número de moles
T es la temperatura
R es la constante de los gases, cuyo valor es = 0.0821 L.atm/K.mol
Además,
Moles = masa (m) / Masa molar (M)
La densidad (d) = Masa (m) / Volumen (V)
Así, la ecuación de gases ideales se puede expresar como:
Dado que:-
Presión = 20 kPa = 20000 Pa
La expresión para la conversión de presión en Pascal a presión en atm se muestra a continuación:
P (Pa) = P (atm)
20000 Pa = atm
Presión = 0.1974 atm
Temperatura = 330 K
d = 1.23 kg/m³ = 1.23 g/L
Masa molar =?
Aplica la fórmula:
0.1974 atm × M = 1.23 g/L × 0.0821 L.atm/K.mol × 330 K
⇒M = 168.82 g/mol
La masa molar del compuesto es: 168.82 g/mol
(b)
Dado que:
Presión = 152 Torr
Temperatura = 298 K
Volumen = 250 cm³ = 0.25 L
Utilizando la ecuación de gases ideales:
R =
Aplicando la fórmula:
152 Torr × 0.25 L = n × 62.3637 L.torr/K.mol × 298 K
⇒n = 0.002045 moles
Dado que:
Masa del gas = 33.5 mg = 0.0335 g
Masa molar =?
La fórmula para calcular los moles se muestra a continuación:
Así,
La masa molar del gas es: 16.38 g/mol
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Explanation:
Initial moles of ethanoic acid = 0.020 mol
At equilibrium, half of the ethanoic acid molecules have reacted.
Thus, moles of ethanoic acid reacted = 0.020 mol * (50% / 100%)
= 0.010 mol
Moles of ethanoic acid remaining = 0.020 mol - 0.010 mol = 0.010 mol
The moles of product gas formed are determined as follows:
0.010 mol CH3COOH * (1 mol / 2 mol CH3COOH)
= 0.005 mol
Consequently, the total moles of gas present in the vessel at equilibrium are 0.010 mol CH3COOH and 0.005 mol
Total gas moles at equilibrium = 0.010 mol + 0.005 mol = 0.015 mol
Next, let’s determine the pressure:
0.020 mol of gas has a pressure of 0.74 atm; so under the same conditions, we find the pressure exerted by 0.015 mol of gas:
P1/n1 = P2/n2
P2 = P1*(n2 / n1)
= 0.74 atm * (0.015 mol / 0.020 mol)
= 0.555 atm
Result: The count of bonding electrons and non-bonding electrons amounts to (4, 18).
Explanation:
The Lewis-dot structure reveals the number of bonding and non-bonding electrons in .
Lewis-dot representation: It illustrates the valence electron count for atoms in a molecule and shows how they bond, as well as any lone pairs of electrons.
In this structure, 'Xe' is the central atom while 'F' is the terminal atom.
Xenon comprises 8 valence electrons, whereas fluorine contains 7.
The total number of valence electrons in is calculated as 8 + 2(7) = 22 electrons
From the Lewis-dot structure, we can determine
The count of electrons involved in bonding = 4
The count of electrons involved in non-bonding (lone-pairs) = 22 - 4 = 18
Thus, the bonding and non-bonding electron counts are (4, 18).
Below is the Lewis-dot structure for .
Answer:
The concentration of P in the pond at equilibrium is 0.034 g/m³
Explanation:
Given the total mass = 49.9 g
1 day = 24 hours
mass per hour;
Incoming mass = (49.9 g / day) * (1 day /24 hr )
= 2.079 g/hr
Outgoing mass = 0
Mass lost due to sunlight = kGiven the half-life = 3.4 hours
For a first-order reaction; k, the rate constant = ln2/t, where t is the half-time
ln 2= 0.693, V= volume
k = 0.693 / t_half = 0.693 / 3.4 = 0.2038 hr⁻¹
Substituting all parameters into the equation kMass lost to sunlight = k V
= Incoming mass per hour / kV
= 2.079 g/hr / (0.2038 hr⁻¹ x 300 m³)
0.034 g/m³