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Aneli
2 months ago
9

Connect in Justin's school, 0.825 of the students participate in a school sport. If there are thousand students in Justin school

, how many participate in a school sport?
Mathematics
2 answers:
Zina [12.3K]2 months ago
7 0

Result: 825.

Detailed breakdown:

babunello [11.8K]2 months ago
3 0
825 represents the figure.


I would appreciate it if you could mark my answer as the best. Thank you!
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Bill buys and sells laptops. Last month Bill bought 50 laptops. He paid £400 for each laptop. He sold 40 of these laptops at a p
PIT_PIT [12445]

Answer:

Yes, Bill surpassed his target by £2,200.

Step-by-step explanation:

The cost for the laptops totals = 50 x 400

= 20,000

He sold 40 laptops with a profit margin of 30%

Calculating that gives (40 x 400) x 1.30

= 20,800

He sold 10 laptops with a profit of 15%

Calculating that gives (15 x 400) x 1.15

= 6900

Thus, the overall sales revenue totals

= 20800 + 6900 = 27,700

7 0
1 month ago
6289002 rounded to the nearest million
Leona [12618]
Utilizing commas makes it simpler to discern the figures.
6,289,002
The digit 6 occupies the millions spot. When rounding, if the subsequent digit is 5 or more, you will round up. Conversely, if the following digit is 4 or less, you will round down. Since the number following 6 is 2, rounding will lead to a decline. The closest million is therefore 6,000,000.
3 0
1 month ago
Trapezoid STUV with vertices S(-3,6),T(0,7),U(1,4),and V(-5,2): (x,y)>(x+7,y-9)​
AnnZ [12381]

Answer:

Please refer below.

Step-by-step explanation:

Given points:

  • S(-3,6),T(0,7),U(1,4),and V(-5,2)

Translation rule:

  • (x,y) → (x+7,y-9)

New coordinates after applying the rule:

  • S'(4, -3), T'(7, -2), U'(8, -5), V'(2, -7)

For the graph, see attached.

The trapezoid highlighted in blue is STUV while the red trapezoid is S'T'U'V'

7 0
2 months ago
In triangle JKL, sin(b°) = three fifths and cos(b°) = four fifths. If triangle JKL is dilated by a scale factor of 2, what is ta
Inessa [12570]

Answer:

Tan(b°) = 3/4, which is equivalent to three fourths (C).

Step-by-step explanation:

Triangle JKL is a right triangle with angle K being the right angle and angle L equal to b°.

We will employ SOHCAHTOA principles from trigonometry to calculate the sides' values.

For triangle ∆JKL:

Sin(b°) = opposite/hypotenuse

Sin(b°) = 3/5

Cos(b°) = adjacent/hypotenuse

Cos(b°) = 4/5

Tan(b°) = 3/4.

From the earlier information, we have the values for each side of triangle ∆JKL.

Please refer to the attached diagram for the triangle (1).

Triangle ∆JKL is scaled with a factor of 2.

This implies multiplying each side of ∆JKL by 2, resulting in:

Opposite side = 2(3) = 6

Adjacent side = 2(4) = 8

Hypotenuse = 2(5) = 10.

To find tan(b°) for the new triangle, we use the tangent ratio:

Tan(b°) = opposite/adjacent.

Tan(b°) = 6/8.

Tan(b°) = 3/4.

Find the diagram for the new triangle included (2).

Diagram 3 provides a depiction of both triangles.

As shown, the angle remains unchanged when a triangle is scaled by a factor.

Thus, we conclude that tan(b°) = three fourths (C).

6 0
2 months ago
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