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Bess
2 months ago
11

Which shows the following expression after the negative exponents have been eliminated?

Mathematics
2 answers:
AnnZ [12.3K]2 months ago
7 0

Response:

a^2b^2

Detailed explanation:

Considering the given algebraic expression:

\dfrac{a^3b^{-2}}{ab^{-4}}, a\neq 0, b\neq 0

The task is to remove the negative exponents and derive the new expression.

Applying the Negative Exponent Rule: x^{-y}=\dfrac{1}{x^y}

Utilizing the Division Law for Exponents: \dfrac{t^x}{t^y}=t^{x-y}

Consequently:

\dfrac{a^3b^{-2}}{ab^{-4}} = a^{3-1}\cdot b^{-2-(-4)}\\$Simplifying\\a^{3-1}\cdot b^{-2-(-4)}=a^2b^{-2+4}\\=a^2b^2\\Therefore:\\\dfrac{a^3b^{-2}}{ab^{-4}}=a^2b^2

babunello [11.8K]2 months ago
5 0

Response:

D

Detailed explanation:

I completed the quiz.

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The details provided in the question are as follows:

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