According to the law of conservation of mass, if an element A has an atomic mass of 2 mass units and element B has an atomic mas

Answer:

The volume of calcium hydroxide solution utilized is 0.0235 mL.

Explanation:

Moles of KHP =

In accordance with the reaction, 2 moles of KHP react with 1 mole of calcium hydroxide, thus 0.0330 moles of KHP will react with;

of calcium hydroxide

The molarity of calcium hydroxide solution = 0.703 M

Volume of calcium hydroxide solution = V

The volume of the calcium hydroxide solution utilized is 0.0235 mL.

A indicates the power lines are what truly conducts (or transmits) the power.
Options B or E are incorrect, as wood is not a good conductor. That's why it's commonly used in homes to retain heat (which comes from electricity), preventing it from escaping.
Option C is also not correct since rubber, similarly, is a poor conductor. Like wood, it acts as an insulator, not transmitting heat (or electricity). This is why rubber gloves are utilized during electrical work.
Option D is valid—most metals are excellent electricity conductors. For instance, copper pans are efficient in cooking because copper effectively conducts heat. Being a metal, this is also why wire cutters have rubber grips; it isolates the user from potential electric shock from the conductive metal. The rubber serves as a barrier to protect against electrocution when handling wires or electricity.

Please ask if you have any inquiries.

Response:

The name of the compound is calcium phosphide.

Clarification:

Calcium phosphide is a salt-like substance formed from calcium and phosphorus in a 2:5 ratio. It is characterized by its red-brown crystalline appearance.

This compound is utilized as a rodenticide for exterminating rats.

Additionally, it can be employed in fireworks.

Answer:

ΔfG°(C₆H₆(g)) = 129.7kJ/mol

Explanation:

Identifying the given parameters from the question;

Vapor pressure = 94.4 mm of Hg

The reaction for vaporization is expressed as;

C₆H₆(l) ⇄ C₆H₆(g)

The equilibrium in terms of activities can be defined as:

K = a(C₆H₆(g)) / a(C₆H₆(l))

The activity for pure substances equals one:

a(C₆H₆(l)) = 1

For an ideal gas phase, activity is approximated as the ratio of partial pressure to total pressure. Under standard conditions:

K = p(C₆H₆(g)) / p°

Where p° = 1atm = 760mmHg is the standard pressure

Thus, we find;

K = 94mmHg / 760mmHg = 0.12421

The formula for Gibbs free energy is:

ΔG = - R·T·ln(K)

Here, R represents the gas constant = 8.314472J/molK

Consequently, the ΔG° for the vaporization of benzene is calculated as:

ΔvG° = - 8.314472 · 298.15 · ln(0.12421)

ΔvG° = 5171J/mol = 5.2kJ/mol

The change in Gibbs free energy for the reaction is determined by the difference between the Gibbs free energy of formation of the products and reactants:

ΔvG° = ΔfG°(C₆H₆(g)) - ΔfG°(C₆H₆(l))

<pThus:

ΔfG°(C₆H₆(g)) = ΔvG° + ΔfG°(C₆H₆(l))

ΔfG°(C₆H₆(g)) = 5.2kJ/mol + 124.5kJ/mol

ΔfG°(C₆H₆(g)) = 129.7kJ/mol