A solution is prepared by adding 1.43 mol of kcl to 889 g of water. the concentration of kcl is ________ molal. a solution is pr

The change in temperature can be expressed as:

By substituting in the known values, we arrive at:

Thus, we obtain the required answer.

The inquiry is incomplete; here is the full question:

One tank of goldfish receives the standard amount of feeding once daily, a second tank is given two feedings a day, and a third tank is fed four times daily throughout a six-week experiment. The body fat of the fish is recorded every day.

Independent Variable-

Dependent Variable-

Constants

Control Group-

Answer:

A) The quantity of food given to the goldfish

B) The body fat of the goldfish

C) -Type of fish in the experiment (goldfish)

Time period for feeding the fish (six weeks)

Shape and size of the tanks

D) group of goldfish receiving the standard feeding amount

Explanation:

The objective of the experiment is to assess how the quantity of food affects the body fat of goldfish. Consequently, the amount of food serves as the independent variable while the body fat acts as the dependent variable.

The control group is the one given the standard feeding amount (once daily). All subjects are goldfish, fed over a six-week duration, with all tanks being the same shape and size, establishing the constants in the research.

84.34 grams of iron (III) chloride is the maximum produced since iron is the limiting reagent, and chlorine gas is in excess.

Explanation:

Balanced equation:

2 Fe + 3 Cl2 → 2 FeCl3​

DATA PROVIDED:

iron =  atoms

mass of chlorine = 67.2 liters

mass of FeCl3 =?

The number of moles of iron will be calculated as

number of moles =

number of moles =

number of moles = 0.52 mol of iron

moles of chlorine gas

number of moles =

Substituting the values into the equation:

n =               (molar mass of chlorine gas = 70.96 g/mol)

   = 947.01 moles

As iron is the limiting reagent therefore

2 moles of Fe lead to 2 moles of FeCl3

0.52 moles of Fe will yield

=

0.52 moles of FeCl3 is produced.

To express this in grams:

mass = n x molar mass

         = 0.52 x 162.2                   (molar mass of FeCl3 is 162.2g/mol)  

          = 84.34 grams