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blsea
17 days ago
9

What was the vertical component of her acceleration during push-off? the positive direction is upward?

Physics
1 answer:
Maru [2.3K]17 days ago
5 0
<span>The solutions to these two equations are: A) a = (F-W)/m = (100-500)/500/g = 9.8*500/500 = +9.8 m/sec^2 B) a1 = +9.8-g = 0</span>
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Determine the final state and temperature of 100 g of water originally at 25.0°c after 50.0 kj of heat have been added to it.
inna [2210]
The heat required to raise the temperature of a substance by \Delta T is represented by
Q=m C_p \Delta T
where m stands for the mass of the substance and C_p indicates the specific heat of the substance. In this situation, we possess m=100~g=0.1~Kg and C_p=4.19~KJ/(Kg K), the specific heat of water.
Consequently, we can ascertain the temperature rise \Delta T:
\Delta T = \frac{Q}{m C_p}= \frac{50~KJ}{0.1~Kg cdot 4.19~KJ/(Kg K)}=119~K =119^{\circ}C
Initially, the water's temperature was 25^{\circ}C, so the end temperature should be
T_f = 25^{\circ}C+119^{\circ}C=144^{\circ}C
Thus, the water is expected to be vapor by now.

However, to give a more accurate statement, during the liquid to vapor transition, the heat added to the system is used to break molecular bonds instead of raising the system's temperature. The heat necessary for the phase change from liquid to vapor is expressed as
Q=m C_L=0.1~Kg \cdot 2265~KJ/Kg=226.5~KJ
where C_L denotes the latent heat of vaporization for water.
Nevertheless, the initial heat input of 50 KJ is less than this requirement, indicating there isn't sufficient heat to finish the liquid-vapor transition. Therefore, the water will remain in the liquid-vapor change phase at a temperature of 100^{\circ}C (the temperature at which the phase change begins)

4 0
25 days ago
Vehicle crumple zones are designed to absorb energy during an impact by deforming to reduce energy transfer to the occupants. Ho
kicyunya [2264]

Answer:

change in KE = -12.95 Btu

Explanation:

provided data

mass = 3000-lbm

initial velocity of vehicle vi = 10 mph = 14ft/s

final velocity of vehicle vf = 0 mph = 0 ft/s

solution

the crumple zone is designed to absorb kinetic energy upon impact

thus the change in KE is related to the initial and final speeds, expressed as:

change in KE = 0.5 × m × (vf² - vi² ).................1

Substituting in the parameters yields:

change in KE = 0.5 × 3000 × (0² - 14.7² )

change in KE = -324135 × \frac{1lbf}{32.174\ lb.ft/s^2} * \frac{1Btu}{778.17 ft.lbf}  

change in KE = -12.95 Btu

5 0
18 days ago
What is the angular acceleration of the pencil when it makes an angle of 10.0 degrees with the vertical?
Sav [2230]
<span>  </span><span>When the net torque and moment of inertia are given, calculating becomes straightforward.

Using the equation torque = I * alpha, where I represents the moment of inertia and alpha is the angular acceleration.

Consequently, 0.098 / 0.000075 results in 1306.666... rad / s^2

While the angular acceleration stays the same, you can also determine the angular velocity at that instance, which is 21.36 rad / s.</span>
6 0
18 days ago
Read 2 more answers
Thermodynamic Properties: Two identical, sealed, and well-insulated jars contain different gases at the same temperature. Each c
Ostrovityanka [2208]

Clarification:

Assuming the gas behaves as an ideal gas in this scenario.

(a)  Thus, the formula for the internal energy of a monoatomic gas can be described as follows.

            U = \frac{3}{2}RT

In the case of a monoatomic ideal gas, there are three types of translational motion, which means there is no rotational motion.

According to the equipartition principle, internal energy can be affected by every form of translational, rotational, or vibrational motion present in the system.

Specifically for Helium, which qualifies as a monoatomic ideal gas,

     U_{He} = \frac{3}{2}RT

For carbon dioxide, a linear triatomic molecule, the possible states include 3 translational motions, 2 rotational motions, and 4 vibrational motions.

However, vibrations add RT to the energy

Therefore, U_{CO_{2}} = \frac{3}{2}RT + \frac{2}{2}RT + 4RT = \frac{13}{2}RT

This leads to having greater internal energy.

(b) Regardless of molecular structure, there are only 3 types of translational movements possible. Thus, the kinetic energy associated with translation is expressed as

               U_{trans} = \frac{3}{2}RT

is the same for both helium and carbon dioxide.

(c)  The ideal gas law is articulated as follows.

                  PV = nRT

In this context, it is stated that

T is identical (same temperature)

n is identical (number of moles of gas)

V is identical (same container)

R remains a constant.

Hence, the pressure is the same for both gases.

3 0
4 days ago
A granite monument has a volume of 25,365.4 cm3. The density of granite is 2.7 g/cm3. Use this information to calculate the mass
Sav [2230]
Given that density = mass/volume

Hence,

Mass = density * volume

Mass = 25,365.4 * 2.7 = 68,486.58 g

<span>The mass of the granite monument rounded to the nearest tenth is 68,485.6 g</span>

5 0
16 days ago
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