Response:
83.1946504051 m
Rationale:
u = Starting velocity = 
s = Distance traveled = 
= Incline = 

Friction coefficient



The calculated stopping distance is 83.1946504051 m
Answer:
Insufficient details provided; please clarify further.
<span>Conclusion: The door's weight results in a CCW torque which can be calculated as
Tccw = 145 N*3.13 m / 2.
You require a CW torque that balances this
Tcw = F*2.5 m*sin20</span>
The maximum speed around this curve before a toolbox made of steel slips off the truck bed is: 14.832 m/s
Further explanation
The centripetal force acts on objects in circular motion, directed towards the circle's center.

F = centripetal force, N
m = mass, Kg
v = linear velocity, m / s
r = radius, m
The velocity directed toward the center of the circle is referred to as linear velocity.
It can be represented as:

r = radius of the circle
f = rotations per second (RPS)
Pickup trucks negotiating a curve are influenced by centripetal forces. To prevent the steel toolbox from slipping off the bed of the truck, the centripetal force acting on it must equal its weight. Should the centripetal force surpass the toolbox's weight, it will fall off.
centripetal force = weight

Thus, the maximum velocity to keep the toolbox secure is:

For a curve with a radius of 22 m, it follows that:

Learn more
The average velocity
Resultant velocity
Velocity position