The key takeaway is that various substances have distinct biomass proportions. Variations in biomass percentages exist due to the differing elemental compositions of these substances. Each biomass is constituted by elements like carbon, hydrogen, nitrogen, and oxygen. For instance, the human body comprises 30% biomass, while the remainder consists of water. The breakdown of various elemental percentages includes carbon (12%), nitrogen (0.6%), hydrogen (62.9%), oxygen (24%), calcium (0.24%), and phosphorus (0.14%). At every level, only 10% of biomass is transferred to the next level, with the remaining 90% being dissipated as heat.
Euglena presenta un color verde gracias al clorofila que se encuentra en los cloroplastos de este organismo, y la estructura corporal situada en su base se llama flagelo.
Explanation:
Las Euglenas son especies que habitan en aguas dulces y saladas, y se encuentran en gran cantidad en cuerpos de agua interiores, donde pueden proliferar y teñir la superficie del agua de zanjas y estanques de un color verde.
Este color verde que producen se debe en gran parte a la clorofila que se halla en sus cloroplastos, la cual es el pigmento responsable del color verde. Este pigmento también es el causante de la coloración en este caso.
Las Euglenas cuentan con una estructura corporal especializada, ubicada en la base de su cola, que les permite moverse.
Esta estructura especializada se denomina flagelo.
determine<span> how earthworms<span> present in </span>soil<span> influence </span>plant development<span>.... this includes tomato, green </span>beans<span> and radish </span>plants<span> in </span>soil<span> samples with</span> earthworms<span>,... For this </span>experiment<span>, the independent variable concerns </span>whether<span> or </span>not<span> the presence of </span>earthworms<span>...</span>
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Utilize the Hardy Weinburg equation pertaining to allelic frequency.
P2+2pq+q2=1
Calculating gives us 174/1378 = 0.126 = q2
Consequently, q2 equals 0.126, which means q = 0.355.
<pGiven that q = 0.355 and noting that p + q = 1, therefore
P = 1 – 0.355 = 0.645.
To determine the population of homozygous dominant (p2);
(0.645)2 x 1378 = 0.416 x 1378 = 573.
For the heterozygous population (2pq);
(2 x 0.645 x 0.355) x 1378 = 0.458 x 1378 = 631.
The number of recessive individuals (q2) equals 174.
