Answer:
$82.3
Step-by-step explanation:
82 multiplied by 25 equals 2050.
Adding 90 gives 2140.
Dividing 2140 by 26 results in 82.3.
No, as the fraction equates to a whole number. Thus, it would actually be an increase.
96 soldiers will remain unassigned and the arrangement will consist of 52 rows.
1 cg equals 10^-5 kg
Thus, 8.25 * 10^2 cg converts to 8.25 * 10^-3 kg
1 nanogram is represented as 10^-12 kg
Consequently, 8.25 * 10^-3 kg is equivalent to 8.25 * 10^9 nanograms
As a result, 8.25 * 10^2 cg is equal to 8.25 * 10^9 nanograms.
1.4×5=7
0.8×10=8
1.4×10=14
1×15=15
15+14+8+7=44
44÷4=11
LQ of 44=11
LQ=10 minutes
11×3=33
UQ= 29 minutes
The Range is 19 minutes
Detailed breakdown:
Commence with the individual boxes. For determining the number of students in each category, calculate Frequency density × The difference in the category. (if it's 5-15, the difference is 10)
This results in the counts of students in each range.
Next, determine the LQ of 44, which is 11.
Then locate the 11th student's score; in this instance, it resides in the 5-15 range. 7 students have already surpassed it, with 8 in the 5-15 range. Hence, the 11th lies within the bounds of 5-15, making the middle 10.
Repeat this process for the UQ.
The interquartile range is calculated as UQ-LQ, yielding 29-10=19 minutes.
I hope this helps, though I'm not entirely sure if my explanation is coherent and I'm unclear on the terminology I've used for these categories.
