A) How many moles of CO2 and H2O are formed from 3.85 mole of propane C3H8 (This calculation needs to be done twice-once fro CO2

Question

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A) How many moles of CO2 and H2O are formed from 3.85 mole of propane C3H8 (This calculation needs to be done twice-once fro CO2

and once for H20.
b) If 0.647 mole of oxygen in used in the burning of propane, how many moles of each of H2O are produced? How many moles of C3H8 are consumed?

The balanced chemical reaction:
1 C3 + 5 O2 = 3CO2 + 4 H2O

Chemistry

1 answer:

castortr0y [2.9K] · Answer 1 · 2026-03-09T07:08:35+03:00

Answer:

11.55 moles of CO2 gas result from 3.85 moles of propane.

15.4 moles of H2O result from 3.85 moles of propane.

b) 0.5176 moles of water result from 0.647 moles of oxygen gas.

0.1294 moles of propane are reacted.

Explanation:

$C_3H_7+5O_2\rightarrow 3CO_2+4H_2O$

a) Amount of propane = 3.85 moles

The reaction indicates that for every mole of propane, 3 moles of carbon dioxide are produced.

Thus, 3.85 moles of propane yield:

$\frac{3}{1}\times 3.85 mol=11.55 mol$ of carbon dioxide.

11.55 moles of CO2 gas result from 3.85 moles of propane.

The reaction also specifies that 1 mole of propane produces 4 moles of water.

Therefore, 3.85 moles of propane will generate:

$\frac{4}{1}\times 3.85 mol=15.4 mol$ of water.

15.4 moles of H2O result from 3.85 moles of propane.

b) Amount of oxygen gas = 0.647 moles

The reaction states that 5 moles of oxygen yield 4 moles of water.

As a result, 0.647 moles of oxygen will produce:

$\frac{4}{5}\times 0.647 mol=0.5176 mol$ of water.

0.5176 moles of water result from 0.647 moles of oxygen gas.

The reaction indicates that 5 moles of oxygen gas interact with 1 mole of propane.

Then, 0.647 moles of oxygen will cause:

$\frac{1}{5}\times 0.647 mol=0.1294 mol$ of propane to react.

0.1294 moles of propane are reacted.