How many molecules of PF5 are found in 39.5 grams of PF5?
1 answer:
Response:
of
can be found in 39.5 grams of
.
Clarification:
Atomic weights: P= 31, F= 19,
The molar mass equals 1 atomic weight of P + 5 atomic weights of
F= 31+5 × 19 = 31+95
=126 g/mole
The number of moles in 39.5 gm of
equals
=
=0.3134 moles
1 mole of any substance encompasses
0.3131 moles comprises 0.3134
Thus, of
can be found in 39.5 grams of
.
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Clarification:
The pertinent information is outlined as follows.
m = 10.0 kg = 10,000 g (since 1 kg = 1000 g)
Starting temperature of block 1, = (100 + 273) K = 373 K
Starting temperature of block 2, = (0 + 273) K = 273 K
Therefore, the heat lost by block 1 equals the heat received by block 2
It's important to convert the temperature into Kelvin as (50 + 273) K = 323 K.
Additionally, the relationship between enthalpy and temperature change is as follows.
=
= 1243550 J
or, = 1243.5 kJ
Next, determine the entropy change for block 1 as follows.
=
=
= -554.12 J/K
Now, the entropy change for block 2 is as follows.
=
=
= 647.49 J/K
Thus, the total entropy is the sum of the entropy changes of both blocks.
= -554.12 J/K + 647.49 J/K
= 93.37 J/K
In conclusion, for this reaction, the outcome is 1243.5 kJ and is 93.37 J/K.
Response:
Here's my calculation
Clarification:
Assume the starting concentrations of H₂ and I₂ are 0.030 and 0.015 mol·L⁻¹, respectively.
We need to determine the initial concentration of HI.
1. We will need a chemical equation with concentrations, so let's compile all the information in one location.
H₂ + I₂ ⇌ 2HI
I/mol·L⁻¹: 0.30 0.15 x
2. Calculate the concentration of HI
3. Plot the initial values
The graph below visualizes the initial concentrations as plotted on the vertical axis.
