Answer:
The salt identified is barium chloride.
Explanation:
The moles of barium sulfate produced are
per the reaction, 1 mole of barium sulfate arises from 1 mole of .
Therefore, 0.0480 moles result from:
of
.
The quantity of used amounts to 10.00 g
Moles of = \frac{10.00 g}{\text{Molar mass}}[/tex]
The molar mass of is 208.33 g/mol
The closest answer to our calculation is .
The correct identification is barium chloride, which has a molar mass of 208.2 g/mol.
Answer:
3.816 × 10⁻³ M
Explanation:
A stock solution of Cu²⁺(aq) is made by dissolving 0.8875 g of solid Cu(NO₃)₂∙2.5H₂O in a 100.0-mL volumetric flask, and then brought up to volume with water. What is the molarity (in M) of Cu²⁺(aq) in this stock solution?
We can derive the following relations:
The moles of Cu²⁺ present in 0.8875 g of Cu(NO₃)₂∙2.5H₂O are:
The molarity of Cu²⁺ is:
Answer: The correct choice is (b).
Explanation:
We have the mass of Magnesium at 97.22 g, and the molar mass of Magnesium is 24.305 g/mol.
Therefore, the calculation for the number of moles is as follows.
Number of moles =
=
= 4 mol
Additionally, it is known that one mole contains atoms/mol. Thus, we calculate the total number of atoms in 4 moles as follows.
= atoms
or, = atoms
Hence, we conclude that in 97.22 grams of Magnesium, there are atoms.
