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hram777
18 days ago
7

5 kg of steam contained within a piston-cylinder assembly undergoes an expansion from state 1, where the specific internal energ

y is u1 = 2709.9 kJ/kg, to state 2, where u2 = 2659.6 kJ/kg.
During the process, there is heat transfer to the steam with a magnitude of 80 kJ. Also, a paddle wheel transfers energy to the steam by work in the amount of 18.5 kJ.
There is no significant change in the kinetic or potential energy of the steam.
Determine the energy transfer by work from the steam to the piston during the process, in kJ.
Engineering
1 answer:
Daniel [215]18 days ago
4 0

Answer:

Energy Transfer = 350 kJ

Explanation:

The net work can be derived from the energy balance equation. Thus, we have:

∆KE + ∆PE + ∆U = Q − W

Where

∆KE = ∆PE = 0 (Since there’s no notable change in either kinetic or potential energy of the steam)

Net work comprises the work done by the paddlewheel, Wpw,

and the work on the piston, Wpiston:

W = Wpw + Wpiston

From the data provided, Wpw = −18.5 kJ,

Summarizing results:

Wpw + Wpiston = Q − ∆U

Wpiston = Q − ∆U − Wpw = Q − m (u2 − u1) − Wpw

Where Q = 80 kJ, m = 5 kg, u2 = 2659.6 kJ/kg, and u1 = 2709.9 kJ/kg

= 80 kJ − 5 kg (2659.6 − 2709.9) kJ/kg − (−18.5 kJ)

= 350 kJ

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b.

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