Answer:
r=0.31
Ф=18.03°
Explanation:
Provided:
Original diameter of bar = 75 mm
Diameter post-cutting = 73 mm
Average diameter of the bar d= (75+73)/2=74 mm
Average length of uncut chip = πd
Average length of uncut chip = π x 74 =232.45 mm
Thus, cutting ratio r
r=0.31
Therefore, the cutting ratio equals 0.31.
Now, the shearing angle is given as
Next by substituting the values
\
Ф=18.03°
Concluding, the shearing angle is 18.03°.
Respuesta:
La temperatura máxima que se puede medir (en °C) es 14170.27°C
Explicación:
Los RTDs son termómetros compuestos de metales cuya resistencia aumenta con la temperatura.
Para un RTD de Clase A, l, Alpha = 0.00385.
La fórmula para el RTD es
Rt = Ro ( 1 + alpha x t)
Donde
Rt es la resistencia a la temperatura t°C,
Ro es la resistencia a 0°C
Alpha es un coeficiente de temperatura constante para un RTD de clase A.
Aquí, Rt = 1000ohms,
Ro se considera como Ra = 18Ohms
Por lo tanto,
1000 = 18 ( 1 + 0.00385t)
Dividiendo ambos lados por 18
1 + 0.00385t = 1000/18
0.00385t = 55.55 - 1
0.00385t = 54.55
t = 54.55/0.00385
t = 14170.27°C
A) τ_max = 59.139 x 10^(6) Pa. B) θ = 0.0228 rad.
It is not feasible to install the wires within the conduit. Explanation: The given dimensions show that the total area is 2.04 square inches while the wires occupy 0.93 square inches. The maximum allowable fill for the conduit is 40%. To determine if placement is possible, compute the conduit’s area at 40% which equates to 0.816 square inches, less than the required area of the wires.
