Write a function: def solution (S) that, given a string S of letters "L" and "R", denoting the types of shoes in line (left or r

Question

1 month ago

9

Write a function: def solution (S) that, given a string S of letters "L" and "R", denoting the types of shoes in line (left or r

ight), returns the maximum number of intervals such that each interval contains an equal number of left and right shoes. For example, given S "RLRRLLRLRRLL", the function should return 4, because S can be split into intervals: "RL, "RRLL", "RL" and "RRLL". Note that the intervals do not have to be of the same size.

Engineering

3 answers:

alex41 [274] · Answer 1 · 2026-02-18T03:26:42+03:00

Answer:

# A function named solution takes a string S as its parameter

def solution(S):

# The count of letter R is stored in letterRcount

# Initialized to zero

letterRcount = 0

# The count of letter L is stored in letterLcount

# Initialized to zero

letterLcount = 0

# The count of 'RL' pairs is assigned to total_count

total_count = S.count("RL")

# Iterating through the input string using for loop

for letter in S:

# If the current letter is R, continue the loop

if(letter == 'R'):

continue

# If R is skipped, increment the letterRcount

letterRcount += 1

# Otherwise, if the letter is L, letterLcount is incremented

elif (letter == 'L'):

letterLcount += 1

# When letterRcount matches letterLcount, total_count is increased

if(letterRcount == letterLcount):

total_count += 1

# The final total_count is returned

return total_count

# The function solution is invoked with a string as argument

print(solution("RLRRLLRLRRLL"))

Explanation:

This script is crafted in Python and comes with thorough commentary. A sample output from the program is included.

grin007 [219] · Answer 2 · 2026-02-18T03:26:41+03:00

grin007 [219]1 month ago

3 0

Answer:

Silakan lihat lampiran. Terima kasih

iogann1982 [279] · Answer 3 · 2026-02-18T03:25:47+03:00

This answer is suitable for all test scenarios.
def solution(S):
right_count = 0
left_count = 0
total_count = 0
for char in S:
if char == 'R':
right_count += 1
elif char == 'L':
left_count += 1
if right_count == left_count:
total_count += 1
right_count = 0
left_count = 0
return total_count