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creativ13
7 days ago
8

1. A glass window of width W = 1 m and height H = 2 m is 5 mm thick and has a thermal conductivity of kg = 1.4 W/m*K. If the inn

er and outer surface temperatures of the glass are 15°C and -20°C. respectively, on a cold winter day, what is the rate of heat loss through the glass?
2. To reduce heat loss through windows, it is customary to use a double pane construction in which adjoining panes are separated by an air space. If the spacing is 10 mm and the glass surfaces in contact with the air have temperatures of 10° C and - 15°C, what is the rate of heat loss from a 1 m times 2 m window? The thermal conductivity of air is ka = 0.024 W/m*K.
Engineering
1 answer:
iogann1982 [279]7 days ago
5 0
1. The window pane has specific dimensions and thermal properties affecting heat transfer rates. 2. The air gap between two glass panes influences the rate of heat loss based on temperature differentials.
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A piece of corroded metal alloy plate was found in a submerged ocean vessel. It was estimated that the original area of the plat
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Answer:

t = 5.27 years

Explanation:

Firstly, the corrosion penetration rate is defined by the formula;

CPR = (KW)/(ρAt)

Where;

K = constant based on exposed area A.

W - mass lost over time

t- duration

ρ - density

A - area exposed

From the problem, we have;

W = 7.6kg or 7.6 x 10^(6) mg

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K is a constant valued at 87.6cm

Rearranging the CPR formula to isolate t, we derive;

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A subway car leaves station A; it gains speed at the rate of 4 ft/s^2 for of until it has reached and then at the rate 6 then th
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Answer:

Refer to the attached document

1512 ft

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V_6 - 0 =  (6 s)(4 ft/s²) = 24 ft/s

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34 < t < 40: Velocity change = area beneath the a–t graph

0 - 42 = 6*a4

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A negative acceleration shows the area lies below the t-axis, indicating a decrease in speed.

Velocity - Time

Since acceleration remains constant or zero, the v−t graph is made up of linear segments connecting the calculated points.

Position change = area beneath the v−t graph

0 < t < 6:  x6 - 0 = 0.5*6*24 = 72 ft

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d = x40 - 0 = 1512 ft

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