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LiRa
2 months ago
6

Which of the following ranges depicts the 2% tolerance range to the full 9 digits provided?

Engineering
1 answer:
Mrrafil [318]2 months ago
4 0

Answer:

Only option C fulfills the criteria.

Explanation:

A quantity's tolerance defines the allowable range of variation for that quantity.

To calculate this, we need to know the magnitude, with the closest value being the average. This average may be provided or can be found using the formula

         x_average = ∑ x_{i} / n

The error or tolerance is determined by comparing the current value with the average expressed as a percentage

         Δx₁ = x₁ / x_average

         tolerance = | 100 - Δx₁  100 |

where bars denote absolute values

Let’s compute these values for each option.

a)

    x_average = (2.1700000 + 2.258571429) / 2

    x_average = 2.2142857145

For x₁, we compute the fluctuation

        Δx₁ = 2.17000 / 2.2142857145

        Tolerance = 100 - 97.999999991

        Tolerance = 2.000000001%

For x₂, we analyze the fluctuation

        Δx₂ = 2.258571429 / 2.2142857145

        Δx₂ = 1.02

        tolerance = 100 - 102.000000009

        tolerance = 2.000000001%

b)

    x_average = (2.2 + 2.29) / 2

    x_average = 2.245

For x₁, we evaluate fluctuation

         Δx₁ = 2.2 / 2.245

         Δx₁ = 0.9799554

         tolerance = 100 - 97.999

         Tolerance = 2.00446%

For x₂, we measure fluctuation

          Δx₂ = 2.29 / 2.245

          Δx₂ = 1.0200445

          Tolerance = 2.00445%

c)

   x_average = (2.211445 + 2.3) / 2

   x_average = 2.2557225

       Δx₁ = 2.211445 / 2.2557225 = 0.9803710

       tolerance = 100 - 98.0371

       tolerance = 1.96%

       Δx₂ = 2.3 / 2.2557225 = 1.024624

       tolerance = 100 - 101.962896

       tolerance = 1.96%

d)

   x_average = (2.20144927 + 2.29130435) / 2

   x_average = 2.24637681

       Δx₁ = 2.20144927 / 2.24637681 = 0.98000043

       tolerance = 100 - 98.000043

       tolerance = 2.000002%

       Δx₂ = 2.29130435 / 2.24637681 = 1.0200000017

       tolerance = 2.0000002%

e)

   x_average = (2 + 2.3) / 2

   x_average = 2.15

   Δx₁ = 2 / 2.15 = 0.93023

   tolerance = 100 - 93.023

   tolerance = 6.98%

   Δx₂ = 2.3 / 2.15 = 1.0698

   tolerance = 6.97%

Examining these outcomes, it is evident that result E does not fall within the specified tolerance range, while the remaining values could align with the desired tolerance based on the required degree of precision. Thus, under stringent precision requirements, option C stands out as the only choice that meets the criteria.

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