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ozzi
2 months ago
15

A Top Fuel Dragster initially at rest undergoes an average acceleration of 39 m/s2 for 3.97 seconds. How far will it go in this

time?
Physics
1 answer:
serg [3.5K]2 months ago
5 0

Answer:

s = 307.34 m

Explanation:

To determine the distance the dragster traveled during the specified time, we will apply the second equation of motion, expressed as follows:

s = Vi t + (0.5)at²

where,

s = distance traveled by the dragster =?

Vi = Initial Velocity = 0 m/s

t = time interval = 3.97 s

a = acceleration = 39 m/s²

Thus,

s = (0 m/s)(3.97 s) + (0.5)(39 m/s²)(3.97 s)²

s = 307.34 m

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A solid sphere is released from the top of a ramp that is at a height h1 = 2.30 m. It rolls down the ramp without slipping. The
Yuliya22 [3333]

Answer:

The horizontal distance d that the ball covers before it lands is 1.72 m.

Explanation:

Given,

Height of ramp h_{1}=2.30\ m

Height of bottom of ramp h_{2}=1.69\ m

Diameter = 0.17 m

We need to determine the horizontal distance d the ball travels before landing.

We need to calculate the time

Using the equation of motion

h_{2}=ut+\dfrac{1}{2}gt^2

t=\sqrt{\dfrac{2h_{2}}{g}}

t=\sqrt{\dfrac{2\times1.69}{9.8}}

t=0.587\ sec

Next, we can find the ball's velocity

Using the kinetic energy formula

K.E=\dfrac{1}{2}mv^2+\dfrac{1}{2}I\omega^2

K.E=\dfrac{1}{2}mv^2+\dfrac{1}{2}\times(\dfrac{2}{5}mr^2)\times(\dfrac{v}{r})^2

K.E=\dfrac{7}{10}mv^2

By applying the conservation of energy

K.E=mg(h_{1}-h_{2})

\dfrac{7}{10}mv^2=mg(h_{1}-h_{2})

v^2=\dfrac{10}{7}\times g(h_{1}-h_{2})

We substitute the values into the equation

v=\sqrt{\dfrac{10\times9.8\times(2.30-1.69)}{7}}

v=2.922\ m/s

Next, we determine the horizontal distance d the ball travels before landing

Using the distance formula

d =vt

Where. d = distance

t = time

v = velocity

We substitute the values into the formula

d=2.922\times 0.587

d=1.72\ m

Thus, the horizontal distance d that the ball travels before it lands is 1.72 m.

8 0
1 month ago
A girl drops a pebble from a high cliff into a lake far below. She sees the splash of the pebble hitting the water 2.00s later.
Yuliya22 [3333]

Answer:

19.62 ms

Explanation:

t = Time taken = 2 s

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s² (we take downward direction as positive)

v=u+at\\\Rightarrow v=0+9.81\times 2\\\Rightarrow v=19.62\ m/sUsing the equations of motion

The pebble's speed upon contact with the water is 19.62 ms

3 0
1 month ago
A particular brand of gasoline has a density of 0.737 g/mLg/mL at 25 ∘C∘C. How many grams of this gasoline would fill a 14.9 gal
Yuliya22 [3333]

Answer:

The answer to your inquiry is Mass = 41230.7 g or 41.23 kg.

Explanation:

Data

Density = 0.737 g/ml

Mass = ?

Volume = 14.9 gal

1 gal = 3.78 l

Process

1.- Convert gallons to liters

1 gal ---------------- 3.78 l

14.9 gal ------------- x

x = 56.44 l

2.- Convert liters to milliliters

1 l ------------------- 1000 ml

56.44 l --------------- x

x = (56.44 x 1000) / 1

x = 56444 ml

3.- Calculate the mass

Formula

Density = \frac{mass}{volume}

Solving for mass

Mass = density x volume

Substituting values

Mass = 0.737 x 56444

Result

Mass = 41230.7 g or 41.23 kg.

3 0
2 months ago
Marcia is given an incomplete chemical equation that includes the number of nitrogen atoms present in the products of the reacti
ValentinkaMS [3465]
If the products have three nitrogen atoms, the reactants must have had the same quantity, as mass is conserved in a chemical reaction.
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Angular speed is calculated as 2.5 rev/sec.
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