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nevsk
1 month ago
10

Velocity is a vector quantity which has both magnitude and direction. ... Net force is also a vector quantity which has both mag

nitude and direction. Using complete sentences, describe the net force acting upon the object during the course of the elliptical orbit. Comment on both the magnitude and the direction.
Physics
2 answers:
kicyunya [3.2K]1 month ago
7 0
When an object traverses an elliptical orbit, its acceleration must be directed toward the two foci of the ellipse to maintain that elliptical motion. Per Newton's second law, F = ma, the net force should be aligned with the direction of the acceleration. As for the net force magnitude, it can be determined using Newton's gravitational law.
inna [3.1K]1 month ago
3 0

The gravitational force represents the net force on an object traveling in an elliptical trajectory. The force vector consistently directs towards the object being orbited by the moving object. In the sun and earth scenario, this vector continually points toward the sun

The exact strength of this force can be calculated using Newton's universal gravitation law. The formula to determine this force's magnitude isF=\frac{GMm}{r^2}.

In this equation G signifies the universal gravitational constant, r denotes the distance between both objects, and M,m represents the masses of the main object and the orbiting body. Thus, it can be inferred that the force magnitude is greater when closer to the central object compared to when farther away.

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Which formula is used to find fluctuation of the shape of body
Softa [3030]

Response:

varn=n1+1ehvkT–1

Explanation:

This formula comes from Einstein's theory.

5 0
1 month ago
A hard rubber rod with an electric potential energy of 5.2 × 10–3 J has a charge of 4.0 µC at the tip. What is the electric pote
Keith_Richards [3271]
1) The electric potential energy can be defined as the product of the electric potential and the associated charge:
U=q V
where
q refers to the charge
V denotes the electric potential

In this scenario, the charge on the rod is q=4.0 \mu C = 4.0 \cdot 10^{-6}C, and the potential energy is U=5.2 \cdot 10^{-3} J, thus we may rearrange the earlier formula to find the electric potential at the tip:
V= \frac{U}{q}= \frac{5.2 \cdot 10^{-3}J}{4.0 \cdot 10^{-6} C}=1300 V=1.3 \cdot 10^3 V

2) Using this same formula, if the charge changes to q=2.0 \mu C = 2.0 \cdot 10^{-6} C, the resulting electric potential will be:
V= \frac{U}{q}= \frac{5.2 \cdot 10^{-3} J}{2.0 \cdot 10^{-6}C}=2600 V = 2.6 \cdot 10^{3}V
8 0
2 months ago
Read 2 more answers
a professional baseball player can pitch a baseball with a velocity of 44.7m/s towards home plate. If a baseball weighs 1.4 N, h
Sav [3153]
To find the mass using a weight of 1.4 N:
1.4/9.8 = 0.1428 kg
The momentum is calculated as 0.1428 multiplied by 44.7, which is 6.38 kgm/s.
3 0
2 months ago
Read 2 more answers
At the end of the school day, at exactly 2:30 pm, a group of students run out of the school building and reach the edge of the s
Yuliya22 [3333]

Explanation:

The initial time is t₁ = 2:30 pm

The final time is t₂ = 2:30:45

We must analyze the students' motion concerning time. The final time exceeds the initial time by 45 seconds.

Change in time,

\Delta t=t_2-t_1\\\\\Delta t=2:30:45-2.30\\\\\Delta t=45\ s

Therefore, this is the solution we need.

3 0
1 month ago
Spin cycles of washing machines remove water from clothes by producing a large radial acceleration at the rim of the cylindrical
Ostrovityanka [3204]

Provided Details:

Cylinder tub diameter = d = 50 cm = 0.50 m

Acceleration = α = 3g

Needed Information:

1. Rotation speed in rev/min = ω =?

2. Tangential velocity in m/s = v =?

Response:

1. ω = 103.5 rev/min

2. v = 2.71 m/s

Explanation:

Centripetal acceleration is defined by

α = ω²r

Where ω refers to angular speed or rotation rate, and r is the radius.

The relationship between diameter and radius is expressed as

r = D/2

r = 0.50/2

r = 0.25 m

Given that the acceleration equals 3g, where g is the gravitational acceleration of 9.81 m/s².

α = ω²r

3g = ω²r

ω² = 3g/r

ω = √(3g/r)

ω = √(3*9.81/0.25)

ω = 10.84 rad/s

To convert rad/s to rev/s, divide by 2π

ω = 10.84/2π

ω = 1.752 rev/s

To convert rev/s to rev/min, multiply by 60

ω = 1.752*60

ω = 103.5 rev/min

Hence, the rotation rate is determined to be 103.5 rev/min

2. The tangential velocity can be computed using

v = ωr

Where ω is the rotation rate in rad/s and r is the radius.

v = 10.84*0.25

v = 2.71 m/s

Thus, the tangential speed is 2.71 m/s.

0 0
2 months ago
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