answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
nevsk
8 days ago
10

Velocity is a vector quantity which has both magnitude and direction. ... Net force is also a vector quantity which has both mag

nitude and direction. Using complete sentences, describe the net force acting upon the object during the course of the elliptical orbit. Comment on both the magnitude and the direction.
Physics
2 answers:
kicyunya [2.9K]8 days ago
7 0
When an object traverses an elliptical orbit, its acceleration must be directed toward the two foci of the ellipse to maintain that elliptical motion. Per Newton's second law, F = ma, the net force should be aligned with the direction of the acceleration. As for the net force magnitude, it can be determined using Newton's gravitational law.
inna [2.7K]8 days ago
3 0

The gravitational force represents the net force on an object traveling in an elliptical trajectory. The force vector consistently directs towards the object being orbited by the moving object. In the sun and earth scenario, this vector continually points toward the sun

The exact strength of this force can be calculated using Newton's universal gravitation law. The formula to determine this force's magnitude isF=\frac{GMm}{r^2}.

In this equation G signifies the universal gravitational constant, r denotes the distance between both objects, and M,m represents the masses of the main object and the orbiting body. Thus, it can be inferred that the force magnitude is greater when closer to the central object compared to when farther away.

You might be interested in
A compact car has a maximum acceleration of 4.0 m/s2 when it carries only the driver and has a total mass of 1200 kg . you may w
inna [2723]
<span>Let F represent the maximum thrust produced by the car's motor. Thus, F = ma = 1300 x 3.0 = 3900 N. After adding the load, F stays the same, leading to the equation F = 1700a, which results in a = F/1700 = 3900/1700 = 2.3 m/s².</span>
3 0
1 month ago
Read 2 more answers
A charge of 4.9 x 10-11 C is to be stored on each plate of a parallel-plate capacitor having an area of 150 mm2 and a plate sepa
Keith_Richards [2873]

Answer:2.53*10^-10F

Explanation:

C=£o£r*A/d

Where £ represents the permittivity constant

£o= 8.85*10^-12f/m

£r=6.3

A=150mm^2=0.015m^2

d=3.3mm= 0.0033m

C=8.85*10^-12*6.3*0.015/0.0033

C=8.85*6.3*10^-12*0.015/0.0033

C=55.755*0.015^-12/0.003

C=8.36/3.3*10^-13+3

C=2.53*10^-10F

7 0
1 month ago
A rotating beacon is located 2 miles out in the water. Let A be the point on the shore that is closest to the beacon. As the bea
serg [3222]

Answer:

v = 3369.2 m/s

Explanation:

The beacon is rotating at an angular speed of

f = 10 rev/min

so we have

\omega = 2\pi f

\omega = 2\pi(\frac{10}{60})

\omega = 1.047 rad/s

We know that

v = r \omega

At this point we have

r = 2 miles = 2(1609 m)

r = 3218 m

So we can conclude with

v = 3218(1.047)

v = 3369.2 m/s

6 0
29 days ago
The intensity level of a "Super-Silent" power lawn mower at a distance of 1.0 m is 100 dB. You wake up one morning to find that
Maru [2948]

Answer:

The correct option is 80 dB.

Explanation:

The transformation of sound intensity level into sound intensity utilizes the formula

[D] = 10 log (I/I₀)

Where I₀ = 10⁻¹² W/m²

[D] results in 100 dB

100 = 10 log (I/I₀)

Log (I/I₀) converts to 10

(I/I₀) = 10¹⁰

I is determined as I₀ × 10¹⁰ = 10⁻¹² × 10¹⁰ = 10⁻² W/m²

Sound intensity inversely relates to the square of the distance from the source.

I ∝ (1/d²)

I can be expressed as k/d²

When d = 1 m, the intensity is 10⁻² W/m²

Thus, 0.01 = k/1

Providing that k = 0.01 W

For d = 20 m, we can calculate I

I = 0.01/20² = 2.5 × 10⁻⁵ W/m²

With four neighbors mowing their lawns concurrently,

I = 4 × 2.5 × 10⁻⁵ = 10⁻⁴ W/m⁻²

The sound intensity level in decibels is represented as

[D] = 10 log (I/I₀)

[D] = 10 log (10⁻⁴/10⁻¹²)

[D] = 10 log (10⁸)

[D] = 10 × 8 = 80dB

4 0
29 days ago
Why didn't the astronauts land on the moon 3.17 answers punchline?
kicyunya [2904]

Answer:

Responses to the 3.17 punchline varied among many individuals, with some suggesting that it was a "full" moon day which prevented the astronauts from landing.

Others claimed that the astronauts took off during daylight hours when the moon was not visible. There were also comments that indicated that 'astro' refers to stars rather than satellites, explaining why they did not land.

A few even noted that 'astro naut' sounds like 'naught,' meaning zero (0), as a possible reason for their failure to land.

3 0
27 days ago
Read 2 more answers
Other questions:
  • In an amusement park rocket ride, cars are suspended from 3.40-m cables attached to rotating arms at a distance of 5.90 m from t
    10·1 answer
  • You, Archimedes, suspect that the king’s crown is not solid gold but is instead gold-plated lead. To test your theory, you weigh
    9·1 answer
  • A student pulls a block over a rough surface with a constant force FP that is at an angle θ above the horizontal, as shown above
    11·2 answers
  • A ball is dropped from the top of a cliff. By the time it reaches the ground, all the energy in its gravitational potential ener
    14·1 answer
  • A food item that is left out of the refrigerator turns brown and forms bubbles and gas. What are the signs that this is a chemic
    6·2 answers
  • Explain the versatility of epithelial tissue
    6·2 answers
  • If a woman weighs 125 lb, her mass expressed in kilograms is x kg, where x is
    9·2 answers
  • A cell membrane consists of an inner and outer wall separated by a distance of approximately 10nm. Assume that the walls act lik
    9·1 answer
  • A man runs at 7.5 m s-1 due east across the deck of a ship which moves at 10.0 m s-1 due north. Determine the resultant velocity
    9·1 answer
  • A sled with no initial velocity accelerates at rate of 5.0 m/s^2 down a hill . How long does it take the sled to go 45 m to the
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!