<span>To determine the quantity of tropical fish a tank can accommodate, calculate the volume by multiplying length, height, and width to obtain cubic centimeters of the aquarium, then divide that result by 10,000. Hence, 60*50*30 results in 90,000 cubic centimeters. Dividing 90,000 by 10,000 yields 9. Therefore, a tank with these measurements can hold 9 tropical fish.</span>
To ascertain the cofactor of
![A=\left[\begin{array}{ccc}7&5&3\\-7&4&-1\\-8&2&1\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D7%265%263%5C%5C-7%264%26-1%5C%5C-8%262%261%5Cend%7Barray%7D%5Cright%5D)
First, eliminate the relevant row and column linked to the specified entries and calculate the determinant of the leftover
matrix while applying alternating signs.
























Therefore, the entries arranged in increasing order of their cofactors values are;

Answer:
60.36 steps West from center
85.36 steps North from center
Step-by-step explanation:
Refer to the attached
Musah's starting point and movement are depicted in the image.
- 1. He moves 50 steps towards the North,
- 2. Next, he moves 25 steps towards the West,
- 3. Then he proceeds 50 steps on a bearing of 315°. We now recognize that North is measured at 0°
or 360°, so a bearing of 315° corresponds to North-West 45°.
Note: According to the Pythagorean theorem, a right triangle at 45° with hypotenuse 'a' will have legs equal to a/√2.
What is the distance West of Musah's final position from the center?
25 + 50/√2 ≈ 60.36 steps
What is the distance North of Musah's final position from the center?
Response: a) 
b) The area has grown by 0.75 square meters.
Detailed breakdown:
Let the room's length be l
Let the room's breadth be 'b'
The area of a rectangle is calculated using the formula:

Per the problem, the room's new area equals 175% of its old area.
Thus, a) The new area of the room is determined as

This indicates a 175% increase in the room's length, resulting in a 175% increase in area.
b) The increase in square meters for Megan's room area is
