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nata0808
2 months ago
10

What is the product? StartFraction 3 k Over k + 1 EndFraction times StartFraction k squared minus 1 Over 3 k cubed EndFraction S

tartFraction k + 1 Over k squared EndFraction StartFraction k minus 1 Over k squared EndFraction StartFraction negative 1 Over k EndFraction StartFraction 1 Over k EndFraction
Mathematics
1 answer:
PIT_PIT [12.4K]2 months ago
4 0

Answer:

StartFraction negative 1 Over k cubed EndFraction

Detailed breakdown:

3k / (k + 1) × (k² - 1) / 3k³

= 3k(k² - 1) / (k + 1)(3k³)

= 3k³ - 3k / 3k⁴ + 3k³

= -3k / 3k⁴

= -1/k³

StartFraction k + 1 Over k squared EndFraction

(k + 1) / k²

StartFraction k minus 1 Over k squared EndFraction

(k - 1)/k²

StartFraction negative 1 Over k cubed EndFraction

= -1/k³

StartFraction 1 Over k EndFraction

= 1/k

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What is the product of 2x2 – 3xy + y2 and 2x – 4y?
AnnZ [12381]

Answer:

C. 4x^3 - 14x^2y + 14xy^2 - 4y^3

Step-by-step explanation:

Given:

Multiplication of 2x^2 – 3xy + y^2 and 2x – 4y

Multiplication refers to the product

(2x^2 – 3xy + y^2) (2x – 4y)

Expand the brackets

= 4x^3 - 8x^2y - 6x^2y + 12xy^2 + 2xy^2 - 4y^3

Combine like terms

= 4x^3 - 14x^2y + 14xy^2 - 4y^3

The result is

C. 4x^3 - 14x^2y + 14xy^2 - 4y^3

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2 months ago
The law of cosines is a^2+b^2-2abcosC=c^2. Find the value of 2abcosC.
zzz [12365]
2ab x cos(C) = 7 since

a^2 + b^2 - 2ab x cos(C) = c^2
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4 0
2 months ago
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There are 28 people on a martial arts course. 13 are female and 15 are male. What fraction of the people are male? ​
lawyer [12517]

Answer:

15/28

Step-by-step explanation:

There are 28 participants total, with 15 being male, resulting in a fraction of 15/28

6 0
2 months ago
Axline Computers manufactures personal computers at two plants, one in Texas and the other in Hawaii. The Texas plant has 40 emp
Zina [12379]

Answer:

a) The likelihood that none of the sampled employees are from the Hawaii plant is 1.74%.

b) The chance that exactly 1 employee from the sample is found working in the Hawaii plant is 8.70%.

c) There is an 89.56% chance that 2 or more employees in the sample are from the Hawaii plant.

d) The probability that 9 employees from the sample are working at the Texas plant is 8.70%.

Step-by-step explanation:

Each employee has two potential employment locations: either Texas or Hawaii. Thus, the binomial probability distribution can be utilized to solve this scenario.

Binomial probability distribution

This distribution defines the probability of achieving exactly x successes in n trials where there are only two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

Here, C_{n,x} denotes the number of ways to choose x objects from a set of n, represented by the subsequent formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of success occurring.

In this context, we know:

The sample comprises 10 employees, therefore n = 10.

a. Calculate the probability that none of the sampled employees are from the Hawaii plant (to 4 decimals)?

Given that 20 out of 60 employees are based in Hawaii:

p = \frac{20}{60} = 0.333

We aim to find P(X = 0).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.333)^{0}.(0.667)^{10} = 0.0174

Thus, the likelihood that none in the sample are from Hawaii stands at 1.74%.

b. Calculate the probability that 1 employee from the sample is from the Hawaii plant?

This is represented as P(X = 1).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{10,1}.(0.333)^{1}.(0.667)^{9} = 0.0870

Therefore, there is an 8.70% possibility that 1 employee in the sample comes from Hawaii.

c. Calculate the probability that 2 or more employees in the sample are from the Hawaii plant?

We can observe two scenarios: either fewer than 2 employees are from Hawaii or 2 and beyond. The combined probabilities equal decimal 1. So:

P(X < 2) + P(X \geq 2) = 1

We seek to find P(X \geq 2).

P(X \geq 2) = 1 - P(X < 2)

From problems a and b, we possess values for both probabilities.

P(X < 2) = P(X = 0) + P(X = 1) = 0.0174 + 0.0870 = 0.1044

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.1044 = 0.8956

Accordingly, the chance that 2 or more employees in this sample operate at the Hawaii plant is 89.56%.

d. Calculate the likelihood that 9 employees in the sample are working at the Texas plant?

This corresponds to the probability found in part b for 1 employee working in Hawaii.

Consequently, there is an 8.70% chance that 9 employees belong to the Texas plant.

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2 months ago
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Answer:

A Type II error occurs when the null hypothesis is not rejected, even when the alternative hypothesis is actually valid.

<pin this="" scenario="" it="" suggests="" that="" the="" new="" program="" genuinely="" improves="" pass="" rate="" yet="" sample="" size="" is="" insufficient="" statistical="" evidence="" to="" prove="" it.="" consequently="" null="" hypothesis="" remains="" accepted.="">

The implication is that the new method may be dismissed or altered despite it being a real enhancement.

Step-by-step explanation:

</pin>
5 0
3 months ago
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