Answer:
The temperature increase of the calorimeter, which is missing in the problem, is necessary for the calculation.
Explanation:
Since the temperature rise (X) is unspecified, we'll express the calculation in terms of X, and demonstrate with an example value.
1) Calorimeter details:
- Temperature increase: X °C
- Heat capacity ratio: 4.87 J / 5.5 °C (given)
- Energy absorbed by calorimeter at X °C rise:
(4.87 J / 5.5 °C) × X
2) Reaction data:
- Heat released: 362 kJ per mole of reactant
- Number of moles consumed: n
- Total energy from reaction:
362 kJ/mol × 1000 J/kJ × n = 362,000 n J
3) Using energy conservation, assuming no heat loss to surroundings, the energy from the reaction equals the energy absorbed by the calorimeter:
- 362,000 n = (4.87 J / 5.5 °C) × X
- n = [(4.87 / 5.5) × X] / 362,000
n = 0.000002446 × X
This means for each degree Celsius rise in calorimeter temperature, 0.000002446 moles of reactant were consumed.
Example:
If the calorimeter temperature increases by 100 °C, then:
- n = 0.000002446 × 100 = 0.0002446 mol