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kvasek
1 month ago
13

Potassium and iodine have formed a bond. Prior to this the potassium gave up an electron. It became a _____. positive ion neutra

l atom negative ion shared ion
Chemistry
2 answers:
VMariaS [2.9K]1 month ago
5 0

Response: The correct option is (a).

Explanation:

A covalent bond refers to one formed by sharing electrons, whereas an ionic bond occurs when electrons transfer from one atom to another.

For instance, potassium possesses 1 valence electron while iodine has 7 valence electrons.

To achieve stability, potassium will relinquish its single valence electron to iodine during their chemical interaction.

This reaction produces KI, or potassium iodide.

When an atom loses an electron, it gains a positive charge and is labeled a cation. Conversely, when an atom acquires an electron, it receives a negative charge and is termed an anion.

Therefore, upon giving up an electron, potassium transforms into a positive ion.

Anarel [2.9K]1 month ago
3 0
<span>When potassium and iodine bond, potassium donates an electron. This results in it becoming a positive ion. positive ion neutral atom negative ion shared ion</span>
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Calculate ΔH and ΔStot when two copper blocks, each of mass 10.0 kg, one at 100°C and the other at 0°C, are placed in contact in
eduard [2782]

Clarification:

The pertinent information is outlined as follows.

m = 10.0 kg = 10,000 g (since 1 kg = 1000 g)

Starting temperature of block 1, T_{1} = 100^{o}C = (100 + 273) K = 373 K

Starting temperature of block 2, T_{2} = 0^{o}C = (0 + 273) K = 273 K

Therefore, the heat lost by block 1 equals the heat received by block 2

mC \Delta T = mC \times \Delta T

10000 g \times 0.385 \times (T_{f} - 100)^{o}C = 10000 g \times 0.385 \times (0 - T_{f})^{o}C

T_{f} - 100^{o}C = 0^{o}C - T_{f}

2T_{f} = 100^{o}C

T_{f} = 50^{o}C

It's important to convert the temperature into Kelvin as (50 + 273) K = 323 K.

Additionally, the relationship between enthalpy and temperature change is as follows.

\Delta H = mC \Delta T

= 10000 g \times 0.385 J/K g \times 323 K

= 1243550 J

or, = 1243.5 kJ

Next, determine the entropy change for block 1 as follows.

\Delta S_{1} = mC ln \frac{T_{f}}{T_{i}}

= 10000 g \times 0.385 J/K g \times ln \frac{323}{373}

= 10000 g \times 0.385 J/K g \times -0.143

= -554.12 J/K

Now, the entropy change for block 2 is as follows.

   \Delta S_{2} = mC ln \frac{T_{f}}{T_{i}}

           = 10000 g \times 0.385 J/K g \times ln \frac{323}{273}

           = 10000 g \times 0.385 J/K g \times 0.168

           = 647.49 J/K

Thus, the total entropy is the sum of the entropy changes of both blocks.

                   = -554.12 J/K + 647.49 J/K\Delta S_{total} = \Delta S_{1} + \Delta S_{2}

           = 93.37 J/K

In conclusion, for this reaction, the outcome is 1243.5 kJ and \Delta S_{total} is 93.37 J/K.

6 0
2 months ago
The speed of light in a vacuum is 2.998 × 10 8 8 m/s. How long does it take for light to circumnavigate the Earth, which has a c
castortr0y [3046]

Answer:- 0.134 seconds

Solution:- The speed is given as 2.988*10^8\frac{m}{s} and the circumference is 24900 miles which is same as the distance light have to covered. It asks to calculate the time required to cover this distance by the light.

Unit conversion is needed from miles to meters since the speed is given in meters per second.

1 mile = 1609.34 meters

Thus, 24900mile(\frac{1609.34meter}{mile})

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Now, speed=\frac{distance}{time}

Rearranged for time, that gives: time=\frac{distance}{speed}

Inserting the values:

time=\frac{40072566meter}{2.988*10^8\frac{meter}{second}}

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Hence, light would take 0.134 seconds to traverse the indicated distance. The answer without the unit is 0.134.

8 0
2 months ago
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First scenario:

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Control: chocolate, cloth type, cloth squares

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DV: growth of the pea plant

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4 0
3 months ago
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