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tankabanditka
1 month ago
9

Which of the following ions is formed when a base is dissolved in a solution? H+ O− OH− SO42+

Chemistry
1 answer:
eduard [2.6K]1 month ago
3 0

Result:

OH⁻

Explanation:

A base is characterized as a substance that reacts with water to produce an excess of hydroxide ions, OH⁻, within an aqueous environment.

For instance, Sodium hydroxide (NaOH)

and Potassium hydroxide (KOH)

Typically, bases consist of specific metallic oxides, metallic hydroxides, and aqueous ammonia.

On the other hand, an acid is known as a proton donor, H⁺, and it reacts with water to release surplus hydroxonium ions in an aqueous solution.

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An experimenter studying the oxidation of fatty acids in extracts of liver found that when palmitate (16:0) was provided as subs
eduard [2645]

Answer:

Fatty acids with an even number of carbons, like palmitate, undergo complete β-oxidation in the liver mitochondria, resulting in CO₂, as acetyl-CoA, their end product, can enter the TCA cycle.

On the other hand, odd-number fatty acids such as undecanoic acid generate acetyl-CoA and propionyl-CoA during their final pass. To allow entry into the TCA cycle, propionyl-CoA must go through additional processes, including carboxylation.

The conversion of CO2 and propionyl-CoA into methylmalonyl-CoA is facilitated by propionyl-CoA carboxylase, a biotin-dependent enzyme that is inhibited by avidin. In contrast, the oxidation of palmitate does not require carboxylation.

Explanation:

Fatty acids with an even number of carbons, such as palmitate, are completely oxidized to CO₂ in the liver mitochondria due to the ability of their oxidation product, acetyl-CoA, to enter the TCA cycle where it is further oxidized to CO₂.

Undecanoic acid is classified as an odd-number fatty acid, consisting of 11 carbon atoms. The last stage of β-oxidation for odd-number fatty acids, like undecanoic acid, produces a five-carbon fatty acyl substrate that is oxidized and split into acetyl-CoA and propionyl-CoA. To enter the TCA cycle, propionyl-CoA needs additional reactions such as carboxylation. Since the oxidation occurs using a liver extract, CO₂ must be supplied externally for propionyl-CoA carboxylation, enabling the complete oxidation of undecanoic acid.

The conversion of CO2 and propionyl-CoA into methylmalonyl-CoA is catalyzed by propionyl-CoA carboxylase, which contains biotin. The function of biotin is to activate CO₂ before it is transferred to the propionate group. The addition of avidin obstructs the complete oxidation of undecanoic acid as it binds very tightly to biotin, thereby hindering the activation and transfer of CO₂ to propionate.

In contrast, palmitate oxidation does not require carboxylation, meaning that the presence of avidin doesn't influence its oxidation.

6 0
5 days ago
A specific amount of energy is emitted when excited electrons in an atom in a sample of an element return to the ground state.Th
castortr0y [2906]
The answer is C. The specific amount of energy released when excited electrons fall back to the ground state produces an emission spectrum. That energy is emitted as photons with precise wavelengths corresponding to the energy differences between levels. Because each element yields a characteristic set of wavelengths, the emission spectrum can be used to identify the element in the sample.
5 0
16 days ago
Read 2 more answers
Which statement is correct? Salts are formed by the reaction of bases with water. Most salts are ionic and are soluble in water.
lorasvet [2668]
<span>Salts result from the reaction between bases and water. - FALSE
</span><span>Most salts are ionic and dissolve in water. - TRUE
</span><span>Most salts are not dissolved in water and do not have electrical charges. - FALSE
</span><span>Solutions containing salt and water are unable to conduct electricity. - FALSE

:)</span>
3 0
1 month ago
Read 2 more answers
A 0.652-g sample of a pure strontium halide reacts with excess sulfuric acid. the solid strontium sulfate formed is separated, d
lorasvet [2668]

Answer:

The original halide's formula is SrCl₂.

Explanation:

  • The chemistry reaction's balanced equation is:

SrX₂ + H₂SO₄ → SrSO₄ + 2 HX, where X indicates the halide.

  • Based on the equation's stoichiometry, 1.0 mole of strontium halide yields 1.0 mole of SrSO₄.
  • The moles of SrSO₄ (n = mass/molar mass) = (0.755 g) / (183.68 g/mole) = 4.11 x 10⁻³ mole.
  • The moles of SrX can thus be calculated as 4.11 x 10⁻³ moles based on stoichiometry from the balanced equation.
  • n = mass / molar mass, thus n =  4.11 x 10⁻³ moles and mass = 0.652 g.
  • The molar mass of SrX₂ is calculated using mass / n = (0.652) / (4.11 x 10⁻³ moles) = 158.62 g/mole.
  • The molar mass of SrX₂ (158.62 g/mole) = Atomic mass of Sr (87.62 g/mole) + (2 x Atomic mass of halide X).
  • Calculating the atomic mass of halide X, we find = (158.62 g/mole) - (87.62 g/mole) / 2 = 71 / 2  g/mole = 35.5 g/mole.
  • This identifies the atomic mass of Cl.
  • Consequently, the original halide's formula is SrCl₂.
4 0
1 month ago
Write the chemical formula for iridium(III) nitride?
lorasvet [2668]

Answer:

Ir(NO2)3

Explanation:

The molar mass is 330.2335, in case that's also required.

3 0
1 month ago
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