If a concentration of 10 fluorescent molecules per μm2of cell membrane is needed to visualize a cell under the microscope, how m

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2 days ago

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any molecules of dye would be needed to visualize a single egg? Enter your answer in scientific notation rounded to two significant figures.

1 answer:

KiRa [971] · Answer 1 · 2026-03-02T22:52:02+03:00

Result: A total of 78,500 dye molecules will be required to visualize a single egg.

Explanation: Each egg cell has an approximate diameter of 100 μm.

We can apply this formula to determine the area of the cell membrane;

A = π $(100)^{2} / 4$ ;

Using π as 3.14, we calculate;

A = 3.14 X $(100)^{2} / 4$

Upon solving, we arrive at;

A = 7,850 μ $m^{2}$

Next, we want to compute the quantity of dye molecules needed for 10 fluorescent molecules per μ $m^{2}$ but;

given that 1 μ $m^{2}$ is equivalent to 7,850 μ $m^{2}$ dye molecules.

Consequently, for 10 fluorescent molecules, the calculation is;

7,850 X 10 = 78,500 dye molecules are required.

Thus, the answer is 78,500 dye molecules.