You throw a baseball at an angle of 30.0∘∘ above the horizontal. It reaches the highest point of its trajectory 1.05 ss later. A

0.00066518 Nm

x₂ = 16 g m₂ / k. The spring's behavior adheres to Hooke's law, expressed as F = k x. For equilibrium illustrated in Newton's diagram, F - W = 0 and k x₁ = m₁ g, leading to k = g m₁ / x₁. In an elevator moving upward with acceleration, the relation adjusts to F - W = m a, which gives F = m (g + a). Compression becomes K x₂ = 4 m (g + 3g), simplifying to x₂ = 4m / k (4g) and ultimately x₂ = 16m2 / k g.

The frequency is calculated to be 735 Hz. Given: Person's distances to speakers are r₁ = 4.1 m and r₂ = 4.8 m. The path difference calculates to d = r₂ - r₁ = 4.8 - 4.1 = 0.7 m. In terms of destructive interference, we derive: λ = v/f, where v is the sound speed of 343 m/s. Using n = 1 gives f = 245 Hz, and for n = 3, f = 735 Hz. Thus, the second lowest frequency for destructive interference is 735 Hz.

Respuesta:

La distancia recorrida es de 25.9 [m]

Explicación:

Se sustituye el valor del tiempo en segundos en la fórmula de desplazamiento

x=10+20*(3) - 4.9*(3)^2

x= 25.9 [metros]

Answer:

The distance measures

Explanation:

According to the problem statement,

The box's width is

There is a gap of length

The first spring's natural length is

The spring constant for the first spring is

The second spring has a natural length of

The second spring's spring constant is

We denote the distance from the center of the box to the left edge as x.

At equilibrium,

The force exerted by the first spring is

while the force from the second spring is

Thus, at equilibrium,

Substituting values gives us

which leads to

resulting in

and finally,

this simplifies to