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1 month ago

"Which of the statements about hypotheses and theories is true?

Physics

1 answer:

Ostrovityanka [3.2K]1 month ago

6 0

Answer:

D) A scientific theory is a comprehensive summary of a hypothesis that has undergone extensive validation through repeated experimentation.

Explanation:

A hypothesis serves as an initial explanation or proposes a potential causal link between various phenomena, offered for a specific observable occurrence. Every scientific theory must be grounded in evidence, which is gathered by testing and challenging hypotheses. Thus, hypotheses form the foundation of a scientific theory.

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Three point charges are positioned on the x axis. If the charges and corresponding positions are +32 µC at x = 0, +20 µC at x =

Sav [3153]

Response:

Magnitude of the electrostatic force acting on the +32 µC charge, $F_{net} = 12 N$

Clarification:

Let q₁ = +32 µC, located at x₁ = 0

q₂ = +20 µC, positioned at x₂ = 40 cm = 0.4 m

q₃ = -60 µC, placed at x₃ = 60 cm = 0.6 m

Define the force magnitude on the +32 µC charge from the +20 µC charge as F₁ (the force on q₁ due to q₂).

$F_{2} = \frac{kq_{1}q_{2} }{x_{2}^2 }$

$F_{2} = \frac{9 * 10^{9} * 32 * 10^{-6} * 20 * 10^{-6} }{0.4^2 }\\F_{2} = 36 N$

Define the force magnitude on the +32 µC charge from the -60 µC charge as F₂ (the force on q₁ due to q₃).

$F_{3} = \frac{kq_{1}q_{3} }{x_{3}^2 }$

$F_{3} = -\frac{9 * 10^{9} * 32 * 10^{-6} * 60 * 10^{-6} }{0.6^2 }\\F_{3} =-48 N$

The resultant electrostatic force on the 32 µC charge is $F_{net} = |F_{2} + F_{3}|$

$F_{net} =| 36 + (-48)| \\F_{net} =|- 12 N| \\ F_{net} = 12 N$

7 0

2 months ago

What is the Physics Primer?

kicyunya [3294]

Answer:

A. a collection of mathematical topics that are pertinent to basic physics.

Explanation:

The physics primer is not the same as the comprehensive online mathematics textbooks. Instead, it comprises topics in mathematics that challenge students and are noteworthy.

Therefore, it can be understood as the framework for resolving physics-related problems. Thus, mathematical skills are integral within physics courses, serving as a preparatory tool for success.

In summary, it represents a compilation of mathematical subjects that are relevant to foundational physics.

7 0

2 months ago

Read 2 more answers

A rod 150 cm long and of diameter 2.0 cm is subjected to an axial pull of 20 kn. if the modulus of elasticity of the material of

Sav [3153]

Given:
a rod with a circular cross section is experiencing uniaxial tension.
Length, L=1500 mm
radius, r = 10 mm
E=2*10^5 N/mm^2
Force, F=20 kN = 20,000 N
[note: newton (unit) in abbreviation is written in upper case, as in N ]

From the details provided, the cross-section area = π r^2 = 100 π =314 mm^2
(i) Stress,
σ
=F/A
= 20000 N / 314 mm^2
= 6366.2 N/mm^2
= 6370 N/mm^2 (to 3 significant figures)

(ii) Strain
ε
= ratio of extension / original length
= σ / E
= 6366.2 /(2*10^5)
= 0.03183
= 0.0318 (to three significant figures)

(iii) elongation
= ε * L
= 0.03183*1500 mm
= 47.746 mm
= 47.7 mm (to three significant figures)

5 0

1 month ago

An elevator is being pulled up from the ground floor to the third floor by a cable. The cable is exerting 4500 newtons of force

serg [3582]

The gravitational force acting on the elevator is 4500N. Explanation: The parameters provided indicate that the force exerted by the elevator is F = 4500 N. The elevator does not accelerate. According to Newton's third law, the force exerted by the cable matches the gravitational force on the elevator, which represents its weight (W), and the elevator's motion stands as follows: F = W + (Mass of elevator × Acceleration of elevator). Therefore, F = W + (Mass of elevator × 0) = W, which leads us to F = 4500 N = W. The net force on the elevator can be expressed as F - W = 0, confirming that the gravitational force on the elevator equals W = 4500N.

3 0

1 month ago