What is the mass of a sample of alcohol (specific heat = 2.4 J/gC), if it requires 4780 J of heat to raise the temperature by 5.

Question

2 months ago

8

43 C? *

1 answer:

VMariaS [2.9K] · Answer 1 · 2026-03-11T21:28:23+03:00

The mass of the alcohol sample is noted to be = m = 367 g

This shows that by increasing the temperature of the specified substance, the alcohol's mass remains at 367 g.

Explanation:

The provided energy for the alcohol sample is q = 4780

We need to determine the mass of alcohol m =?

It’s given that

The specific heat is represented by = c = 2.4 J/gC

The temperature change is ΔT = 5.43° C

To calculate the mass of the alcohol, we proceed as follows:

The equation is c = $\frac{q}{mt}$

We can isolate m on the left side of the equation,

m = $\frac{q}{ct}$

mass of alcohol (m) = $\frac{4780}{(2.4)( 5.43)}$

m = 367 g

Thus, the mass of the alcohol sample is

m = 367g

It takes 4780 J of heat to elevate the temperature by 5.43 C, resulting in a mass of 367 g of alcohol.