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leva
1 month ago
10

Element X reacts with element Y to give a product containing X3+ ions and Y2− ions.

Chemistry
1 answer:
KiRa [2.9K]1 month ago
5 0

Answer:

X₂Y₃

Explanation:

X⇒X³⁺ + 3e⁻  /×2

Y + 2e⁻ ⇒ Y²⁻  /×3

2X⇒2X³⁺ 6e⁻

3Y + 6e⁻⇒ 3Y²⁻

2X + 3Y ⇒2X³⁺ + 3Y²⁻    ⇒  X₂Y₃

To balance the electrons, we can shorten the equations from both sides. The next step is to combine these two half-processes. Element Y captures two electrons from element X, resulting in X becoming positively charged while Y acquires a negative charge. This suggests that element Y likely possesses a higher electronegativity.

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A laboratory analysis of an unknown sample yields 74.0% carbon, 7.4% hydrogen, 8.6% nitrogen, and 10.0% oxygen. What is the empi
Tems11 [2777]
Assuming we have a 100g sample, the mass of each element is as follows:
C: 74 g
H: 7.4 g
N: 8.6 g
O: 10 g
Next, we calculate the moles of each by dividing the mass of each element by its molar mass:
C: (74 / 12) = 6.17
H: (7.4 / 1) = 7.4
N: (8.6 / 14) = 0.61
O: (10 / 16) = 0.625
Now, we take the smallest value to determine the ratio:
C: 10
H: 12
N: 1
O: 1
Thus, the empirical formula can be expressed as
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3 0
2 months ago
If you weigh 100 kg, how much would you weigh if all the water were removed from your body? A65 kg B45 kg C50 kg D35 kg
castortr0y [3046]
The answer is B. 45k. Human bodies contain approximately 60 to 70% water.
5 0
2 months ago
Now that Snape and Dumbledore has taught you the finer points of hydration calculations they have a slightly more challenging pr
eduard [2782]

Answer:

The integer value of x in the hydrate is 10.

Explanation:

Molarity=\frac{Moles}{Volume(L)}

Molar concentration of the solution = 0.0366 M

Volume of the solution = 5.00 L

Moles of hydrated sodium carbonate = n

0.0366 M=\frac{n}{5.00 L}

n=0.0366 M\times 5 mol=0.183 mol

Weight of hydrated sodium carbonate = n = 52.2 g

Molar mass of hydrated sodium carbonate = 106 g/mol + x * 18 g/mol

n=\frac{\text{mass of Compound}}{\text{molar mass of compound}}

0.183 mol=\frac{52.2 g}{106 g/mol+x\times 18 g/mol}

106 g/mol+x\times 18 g/mol=\frac{52.2 g}{0.183 mol}

By solving for x, we arrive at:

x = 9.95, approximating to 10

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6 0
2 months ago
The value of delta G at 141.0 degrees celsius for the formation of phosphorous trichloride from its constituent elements,
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The appropriate answer is option E. Gibbs free energy can be expressed using the equation: ΔG = ΔH - TΔS, where ΔH denotes the change in enthalpy of the reaction, T is the reaction temperature, and ΔS signifies entropy change. For our calculations, we have ΔH = -720.5 kJ/mol which converts to -720500 J/mol (given that 1 kJ = 1000 J), ΔS = -263.7 J/K, and T = 141.0°C, which equals 414.15 K. Consequently, the Gibbs free energy for the specified reaction at 141.0°C is calculated as -611.3 kJ/mol.
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2 months ago
In the first step of glycolysis, the given two reactions are coupled. reaction 1:reaction 2:glucose+Pi⟶glucose-6-phosphate+H2OAT
lorasvet [2795]

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Explanation:

According to our understanding:

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For a reaction to be classified as spontaneous, the Gibbs free energy must yield a negative value.

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ATP + H₂O ⟶ ADP + Pi, ΔG = -30.5 kJ/mol\rightarrow

From this, we can conclude that ΔG being negative indicates that reaction 2 is indeed spontaneous.

8 0
1 month ago
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