Answer:
The salt identified is barium chloride.
Explanation:
The moles of barium sulfate produced are 
per the reaction, 1 mole of barium sulfate arises from 1 mole of 
.
Therefore, 0.0480 moles result from:
of .
The quantity of used amounts to 10.00 g
Moles of = \frac{10.00 g}{\text{Molar mass}}[/tex]
The molar mass of is 208.33 g/mol
The closest answer to our calculation is 
.
The correct identification is barium chloride, which has a molar mass of 208.2 g/mol.
Ca3(PO4)2 is the correct formula.
I predict that there will be an increase in the seconds recorded in the time column. This is because, as more water is mixed with sodium thiosulfate, its concentration diminishes in each flask. Additionally, a lower concentration results in a slower reaction rate since fewer molecules of sodium thiosulfate means there are less frequent collisions with sulfuric acid. With fewer collisions occurring in the reaction, it takes a longer time for the reaction to complete, leading to increased time when sodium thiosulfate is diluted.
Explanation:
I can confirm that this explanation is accurate.
Answer:
vHe / vNe = 2.24
Explanation:
To determine the velocity of an ideal gas, one should apply the formula:
v = √3RT / √M
In this equation, R represents the gas constant (8.314 kgm²/s²molK); T refers to temperature, and M indicates the molar mass of the gas (4x10⁻³kg/mol for helium and 20.18x10⁻³ kg/mol for neon). Hence:
vHe = √3×8.314 kgm²/s²molK×T / √4x10⁻³kg/mol
vNe = √3×8.314 kgm²/s²molK×T / √20.18x10⁻³kg/mol
The ratio simplifies to:
vHe / vNe = √3×8.314 kgm²/s²molK×T / √4x10⁻³kg/mol / √3×8.314 kgm²/s²molK×T / √20.18x10⁻³kg/mol
vHe / vNe = √20.18x10⁻³kg/mol / √4x10⁻³kg/mol
vHe / vNe = 2.24
I hope it assists you!
