Response:
12 --> 15
This reflects a 25% rise.
To calculate the increase: New Number - Original Number
15 - 12 = 3
Next, divide the increase by the original number and multiply the result by 100.
3/12 = 1/4 = 0.25 x 100 = 25
Thus, the percentage increase amounts to 25%
Answer:
The total weight of 15 bags is 258.21 kilograms.
The combined volume of 15 bags is 2.222 cubic yards.
Step-by-step explanation:
In terms of dimensions, a pound is equivalent to 0.453 kilograms, and a cubic yard is equal to 27 cubic feet. We'll calculate the weight and volume for 15 bags by utilizing these conversions:
Weight
The total weight of 15 bags equals 258.21 kilograms.
Volume
The total volume of 15 bags sums up to 2.222 cubic yards.
a) P(identified as explosive) equals P(actual explosive & identified as explosive) + P(not explosive & identified as explosive) = (10/(4*10^6))*0.95+(1-10/(4*10^6))*0.005 = 0.005002363. Thus, the probability that it actually contains explosives given that it's identified as containing explosives is (10/(4*10^6))*0.95/0.005002363 = 0.000475. b) Let the probability of correctly identifying a bag without explosives be a. Therefore, a = 0.99999763, approximately 99.999763%. c) No, even if this becomes 1, the true proportion of explosives will always be below half of the total detected.
Answer:
The range of cheerleaders' heights lies within the interval [58, 74)
It includes all real numbers from 58 inches and above, but below 74 inches.
Step-by-step explanation:
we have
Separate the combined inequality into two distinct inequalities
-----> inequality A
-----> inequality B
Solve inequality A
Subtract 28 from both sides
Split by 4 on both sides
Reformulate
Address inequality B
Subtract 28 from both sides
Split by 4 on both sides
consequently
The height range of the cheerleaders is the interval [58, 74)
It consists of every real number starting from 58 inches and less than 74 inches
We can formulate the trajectory of the parabola using the vertex form equation: y = a (x – h)^2 + k. The coordinates for the vertex are at h and k, representing the peak height, thus h = 250 and k = 120. Consequently, the equation becomes y = a (x – 250)^2 + 120. At the starting point where x = 0 and y = 0, we find a: 0 = a (0 – 250)^2 + 120, which simplifies to 0 = a (62,500) + 120, leading to a = -0.00192. The complete equation is y = -0.00192 (x – 250)^2 + 120. To determine y when x = 400, we substitute: y = -0.00192 (400 - 250)^2 + 120, yielding y = 76.8 ft. Hence, the ball clears the tree by 76.8 ft – 60 ft = 16.8 ft.
