For the RC circuit and the RL circuit, assume that the period of the source square wave is much larger than the time constant fo
r each. Make a sketch of vR(t) as a function of t for each of the circuits?
1 answer:
Answer with Explanation:
Concepts and reasoning
The principle for addressing this question is that a capacitor in an RC circuit allows current to flow until fully charged. Once charged, it prevents any further current from moving through. Conversely, the situation is different with an inductor in an RL circuit. In accordance with Faraday's law, an inductor generates an electromagnetic force to counteract the applied voltage, but when no change in flux occurs, it behaves akin to a regular wire as if the inductor is absent.
In the accompanying diagram, a resistor is connected in series with a capacitor.
As we observe
the voltage across both the capacitor and the source.Voltage across a resistor in an RC circuit.
Voltage across a resistor in an RL circuit.
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Complete Question
An aluminum "12 gauge" wire measures a diameter of 0.205 centimeters. The resistivity ρ of aluminum is 2.75×10−8 ohm-meters. The electric field E in the wire varies over time as E(t)=0.0004t2−0.0001t+0.0004 newtons per coulomb, where time is recorded in seconds.
At time 5 seconds, I = 1.2 A.
We need to find the charge Q traveling through a cross-section of the conductor from time 0 to time 5 seconds.
Answer:
The charge is
Explanation:
The question indicates that
The wire’s diameter is
The radius of the wire is
Aluminum's resistivity is
The electric field variation is described as
The charge is effectively given by the equation
Where A is the area expressed as
Thus,
Therefore
By substituting values
The question states that t = 5 seconds