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joja
1 month ago
9

tas watches as his uncle changes a flat tire on a car. his uncle raises the car using a machine called a jack. each time his unc

le pushes down on the jack handle, the car rises up. tas sketches the jack and labels it using the symbols f, to represent force, and d, to represent distance. he uses large and small letters to compare the sizes of the forces and distances. which set of labels is correct for the side of the jack that tas’s uncle pushes on? a large f and a small d a small f and a small d a large f and a large d a small f and a large d
Physics
2 answers:
serg [3.5K]1 month ago
8 0
Small f and large L.

Machines are necessary for people to magnify their strength.

Humans cannot lift a car unaided.

Through leverage or hydraulic principles, machines augment your force.

By applying a strong leverage, you can achieve considerable motion with little effort, consequently enabling the other side to move shorter distances with a higher force.

I hope this is helpful. Please let me know.
Softa [3K]1 month ago
7 0

The answer is

-Small f and large D.

The explanation:

-A car jack acts as a machine, defined as an apparatus that aids individuals in exerting force more easily.

-Hence, by applying a small force to the jack, the height at which the car is elevated increases.

Machines are essential for people to amplify their strength; without them, lifting a car would be impossible.

Employing leverage or hydraulic principles, machines enhance your exerted force.

Utilizing a greater lever allows for extensive movement with minimal force, resulting in the opposite side moving shorter distances with an increased force.

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The amount of work performed by a system at consistent pressure is defined by the following equation:
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where
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Plugging the values given in this case into the formula gives us
W=p (V_f -V_i)=(1.00 atm)(2.00 L-1.00 L)=1.00 L\cdot atm

Considering that 1 atm \cdot L = 101.3 J, the result for the work done becomes
W= 1.00 atm \cdot L = 101.3 J
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Details that are not provided: the problem figure is included.

We can address the exercise by applying Poiseuille's law. This law indicates that for a fluid flowing in a laminar manner within a confined pipe,

\Delta P = \frac{8 \mu L Q}{\pi r^4}

where:

\Delta P represents the pressure difference across the two ends

\mu denotes the viscosity of the fluid

L signifies the length of the pipe

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This law can be utilized for the needle, allowing us to compute the pressure difference between point P and the needle's end. In this scenario, we have:

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Answer:

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