Response:
The new resistance is half of the original resistance.
Explanation:
Resistance in a wire is represented by:
= resistivity of the material
L and A are the physical dimensions
If a wire is exchanged for one where all linear dimensions are doubled, i.e. l' = 2l and r' = 2r
The updated resistance of the wire can be calculated as follows:
The new resistance equals half of the original resistance. Thus, this provides the solution needed.
Since the absolute values of the charges are identical, the changes in potential energy remain equivalent. Consequently, the changes in kinetic energy will also match. We have:
1 = Ke/Kp = m_e * v_e^2 / m_p * v_p^2, which simplifies to:
v_e/v_p = sqrt(m_p/m_e),
indicating that the velocity of the electron is sqrt(m_p/m_e) times greater than that of the proton.
Answer:
Explanation:
To convert from gram / centimeter³ to kg / m³
gram / centimeter³
= 10⁻³ kg / centimeter³
= 10⁻³ / (10⁻²)³ kg / m³
= 10⁻³ / 10⁻⁶ kg / m³
= 10⁻³⁺⁶ kg / m³
= 10³ kg / m³
Thus, to convert the quantity in gm / cm³ into kg/m³, you need to multiply by 10³
2.33 gram / cm³
= 2.33 x 10³ kg / m³.
Given
m1(mass of red bumper): 225 Kg
m2 (mass of blue bumper): 180 Kg
m3(mass of green bumper): 150 Kg
v1 (velocity of red bumper): 3.0 m/s
v2 (final velocity of the combined bumpers):?
The principle of momentum conservation indicates that the momentum before impacts equals the momentum after impacts. This can be represented mathematically as:
Pa= Pb
Pa symbolizes the momentum prior to collision and Pb refers to momentum after collision.
Applying this principle to the aforementioned scenario results in:
Momentum pre-collision= momentum post-collision.
Momentum pre-collision = (m1+m2) x v1 =(225+180)x 3 = 1215 Kgm/s
Momentum post-collision = (m1+m2+m3) x v2 =(225+180+150)x v2
=555v2
We now know that Momentum pre-collision equals momentum post-collision.
<presulting in="">
1215 = 555 v2
v2 = 2.188 m/s
Consequently, the final velocity of the combined bumper cars is 2.188 m/s
</presulting>
