A rocket starts from rest and moves upward from the surface of the earth. for the first 10.0 s of its motion, the vertical accel

Question

1 month ago

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eration of the rocket is given by ay=(2.60m/s3)t, where the +y-direction is upward.

1 answer:

kicyunya [3.2K] · Answer 1 · 2026-03-27T20:27:16+03:00

5 0

The rocket's acceleration is described here as

$a_y = 2.60* t$

now recognizing that

$\frac{dv}{dt} = 2.60t$

we integrate both sides

$\int dv = \int 2.60t dt$

$v = 2.60\frac{t^2}{2}$

$v = 1.30 t^2$

given that the rocket is accelerating for a duration of t = 10 s

thus, we have

$v = 1.30 * 10^2$

$v = 130 m/s$

consequently, after t = 10 s, the rocket will achieve a speed of 130 m/s in an upward direction