The attached graph illustrates the region. The centroid's coordinates are (5/3, 1). The centroid's coordinates are determined by averaging the coordinates of the area; Oₓ = (Aₓ+Bₓ+Cₓ)/3 = (0+1+4)/3 = 5/3 and O(y) = (A(y) + B(y) + C(y)) = (0+3+0)/3=3/3=1.
<span>Denote x as the interval, then:
186 = 50 + 3 + (3+x) + (3+2x) + (3+3x) + (3+4x) + (3+5x) + (3+6x) + (3+7x)
186 = 74 + 28x
x = 4
Age of the eldest son = 3+7x = 3+28 = 31.</span>
Answer:
3
/2
Step-by-step explanation:
Given that AC = BC, this is an isosceles triangle.
Since CD is perpendicular to AB, we find AD = DB = 0.5AB = 3/2
Now considering triangle ACD,[TAG_17]]
we will use Pythagoras' theorem,
AC =
AC = 3
/2
:-)
The likelihood that at least one trip occurs before Isabella's birth is 0.7627.
Step-by-step explanation:
In this scenario, Isabella has invented a time machine, but she lacks control over where she travels. Each use of the device holds a 0.25 probability of leading her to a time preceding her birth. Over the initial year of trials, she operates her machine 5 times. If we assume every journey has an equal chance of going back in time, we can calculate the odds that at least one of these trips occurs before she was born. Here's the calculation:
The probability of traveling to a time prior to her birth is 0.25.
The chance of not traveling back in time, given that the machine is used 5 times:
⇒ 
⇒ 
⇒ 
The probability that at least one trip goes before Isabella's birth is equal to 1 minus the probability of not traveling back to that period:
⇒ 
⇒ 
Consequently, the chance that at least one trip travels before Isabella's birth is 0.7627.