Answer:
010100000001101000101
Explanation:
To identify the location of an error in data bits, the SEC code is utilized. For a 16-bit data word, 5 check-bits are necessary to create the SEC code. The values of the check bits are:
C16=0, C8=0, C4=0, C2=0, C1=1
Hence, the resulting SEC code is 010100000001101000101
Response:
C++ code provided below with suitable annotations
Clarification:
pattern.cpp
#include<iostream>
using namespace std;
void printCross(int n)
{
int i,j,k;
if(n%2) //odd number of lines
{
for(int i=n;i>=1;i--)
{
for(int j=n;j>=1;j--)
{
if(j==i || j==(n-i+1))
cout<<j;
else
cout<<" ";
}
cout<<"\n";
}
}
else //even number of lines
{
for(int i=1;i<=n;i++)
{
for(int j=1;j<=n;j++)
{
if(j==i || j==(n-i+1))
{
cout<<" "<<j<<" ";
}
else
cout<<" ";
}
cout<<"\n";
}
}
void printForwardSlash(int n)
{
if(n%2)
{
for(int i=n;i>=1;i--)
{
for(int j=n;j>=1;j--)
{
if(j==n-i+1)
{
cout<<j;
}
else
cout<<" ";
}
cout<<"\n";
}
}
else
{
for(int i=1;i<=n;i++)
{
for(int j=1;j<=n;j++)
{
if(j==(n-i+1))
{
cout<<j;
}
else
cout<<" ";
}
cout<<"\n";
}
}
}
void printBackwardSlash(int n)
{
if(n%2) // odd number of lines
{
for(int i=n;i>=1;i--)
{
for(int j=n;j>=1;j--)
{
if(j==i)
{
cout<<j;
}
else
cout<<" ";
}
cout<<"\n";
}
}
else //even number of lines
{
for(int i=1;i<=n;i++)
{
for(int j=1;j<=n;j++)
{
if(j==i)
{
cout<<j;
}
else
cout<<" ";
}
cout<<"\n";
}
}
}
int main()
{
int num;
char ch;
cout<<"Create a numberes shape that can be sized."<<endl;
cout<<"Input an integer [1,50] and a character [x,b,f]."<<endl;
cin>>num>>ch;
if(ch=='x' || ch=='X')
printCross(num);
else if(ch=='f' || ch=='F')
printForwardSlash(num);
else if(ch=='b' || ch=='B')
printBackwardSlash(num);
else
cout<<"\nWrong input"<<endl;
return 0;
}
Response:
I am not familiar with coding languages, but I can demonstrate how you might do it in Python
myAlarm():
arm = True
code = "secret message"
myAlarm()
main():
deactivate = input(">>> ")
if deactivate = myAlarm.code:
arm = False
I still feel a bit unclear about the question.
(I work as a game developer and code daily)
Answer:
C. you possess insurance documentation
Explanation:
Being a resident does not automatically grant permission to operate a vehicle. For instance, a person might have residency but might also have a suspended license, which means they are unable to drive.
Typically, insurance applies to the CAR rather than the individual. Therefore, the general guideline is:
A different person is permitted to drive your vehicle if you possess proof of insurance.
#include <iostream>
using namespace std;
void OutputMinutesAsHours(double origMinutes) {
double hours = origMinutes / 60.0;
cout << hours;
}
int main() {
OutputMinutesAsHours(210.0); // This function will also be called with 3600.0 and 0.0.
cout << endl;
return 0;
}
The lines highlighted in bold perform the conversion from minutes to hours by dividing the input minutes by 60, since there are 60 minutes in one hour. The parameter origMinutes is a double, so the division uses 60.0 to keep consistent data types. Running this code with 210.0 will output 3.5.
