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yawa3891
22 days ago
11

Select the correct answer from each drop-down menu.

Chemistry
2 answers:
lions [2.6K]22 days ago
8 0

The direction of the arrow indicates that the bond involving the chlorine atom and the fluorine atom is nonpolar. The fluorine atom pulls the electrons in the bond with greater strength, resulting in the chlorine atom being a little positive.

Explanation:

  • The bond formed between chlorine and fluorine displays nonpolar characteristics because both atoms contribute an equal share of electrons within the bond. Examples such as H2, F2, and Cl2 illustrate this concept well.
  • Both chlorine and fluorine are electronegative elements, yet fluorine resides above chlorine in the periodic table. Fluorine's position above chlorine gives it a somewhat higher electronegativity compared to chlorine. This explains why fluorine molecules attract electrons more efficiently than chlorine atoms, resulting in chlorine exhibiting a slight positive charge in bonds between Cl and F.

alisha [2.7K]22 days ago
5 0

Answer:

The bond between chlorine and fluorine is depicted as polar by the arrow. The fluorine atom exerts a stronger pull on the shared electrons, resulting in the chlorine atom having a slightly positive charge.

Explanation:

A covalent bond is formed when atoms share electrons to create a molecule. These bonds typically occur between nonmetals like hydrogen (H), oxygen (O), and chlorine (Cl).

Covalent bonds can be classified as either polar or nonpolar. This classification is based on the types of atoms involved: if both atoms are the same, the bond is nonpolar (as neither atom will attract the electrons more strongly). Conversely, if the atoms differ, the bond gains a polar character as the more electronegative atom pulls the electron pair towards it, thus creating polarity.

In this instance, the bond is between two nonmetals, classifying it as a covalent bond, and as per the earlier definition, it is indeed a polar bond, as indicated by the arrow in the image.

The arrow signifies that the electrons shared between these two elements are drawn more towards fluorine because of its higher electronegativity. Given that electrons are negatively charged, fluorine will take on a slightly negative charge, whereas chlorine will have a slight positive charge.

Thus, the arrow indicates that the bond between chlorine and fluorine is polar. The shared electrons in this bond are attracted more strongly by the fluorine atom, while the chlorine atom carries a slightly positive charge.

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Tems11 [2403]
Assuming we have a 100g sample, the mass of each element is as follows:
C: 74 g
H: 7.4 g
N: 8.6 g
O: 10 g
Next, we calculate the moles of each by dividing the mass of each element by its molar mass:
C: (74 / 12) = 6.17
H: (7.4 / 1) = 7.4
N: (8.6 / 14) = 0.61
O: (10 / 16) = 0.625
Now, we take the smallest value to determine the ratio:
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H: 12
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1 month ago
7.744 Liters of nitrogen are contained in a container. Convert this amount to grams.
lorasvet [2542]

Answer:

9.69g

Explanation:

To find the needed outcome, we first need to determine the number of moles of N2 present in 7.744L of the gas.

1 mole of gas takes up 22.4L at STP.

Thus, X moles of nitrogen gas (N2) will fill 7.744L, meaning

X moles of N2 = 7.744/22.4 = 0.346 moles

Next, we will convert 0.346 moles of N2 to grams to achieve the result sought. The calculation goes as follows:

Molar Mass of N2 = 2x14 = 28g/mol

Number of moles N2 = 0.346 moles

Find the mass of N2 =?

Mass = number of moles × molar mass

Mass of N2 = 0.346 × 28

Mass of N2 = 9.69g

Hence, 7.744L of N2 consists of 9.69g of N2

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Answer:

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Explanation:

To create a fake iron ball out of gold, we must ensure that its mass matches that of the iron ball. Therefore, we first find the volume of the iron ball using the provided diameter, applying the formula of 4/3 pi r^3.

Given the diameter d = 6 cm; thus, the radius r = 3 cm (d/2).

We calculate the volume of the iron ball: 4/3 * 3.14 * 3^3 = 113.04 cm^3.

The corresponding mass of the iron ball is the volume multiplied by its density: 113.04 * 5.15 g/cm^3 = 582.156 g.

This value represents the mass for the gold ball; now we determine the volume of the gold ball using its density.

Volume of gold ball = mass of gold ball/density of gold = 582.156 g/19.3 g/cm^3 = 30.1635 cm^3.

So this volume must correspond to a hollow sphere with an outer radius R = 3 cm and an unknown inner radius r.

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