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Debora
1 month ago
7

What is the oxidation state of selenium in SeO3?​

Chemistry
1 answer:
eduard [2.7K]1 month ago
8 0

Response: The oxidation state of selenium in SeO3 is +6

Clarification:

SeO3 represents selenium trioxide.

- The oxidation state of SeO3 is 0 (as it remains stable and carries no charge)

- The oxidation number of oxygen (O) in SeO3 is -2

- The oxidation state of selenium in SeO3 is defined as Z (where Z is an unknown value)

Thus, SeO3 = 0

Z + (-2 x 3) = 0

Z + (-6) = 0

Z - 6 = 0

Z = 0 + 6

Z = +6

Hence, the oxidation state of selenium in SeO3 is +6

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The graph above shows the changes in temperature recorded for the 2.00 l of h2o surrounding a constant-volume container in which
Alekssandra [3086]

Answer:

25.2 kJ

Explanation:

The full question can be found in the image linked to this response.

It's important to highlight that the heat absorbed by the 2.00 L of water for increasing its temperature from the beginning to the end comes solely from the burning of benzoic acid, as there are no heat transfers to the container or the surroundings.

To find the heat released from benzoic acid combustion, we simply measure the heat needed to warm the water.

Q = mCΔT

To find the mass of the water,

Density = (mass)/(volume)

Mass = Density × volume

Density = 1 g/mL

Volume = 2.00 L = 2000 mL

Mass = 1 × 2000 = 2000 g

C = specific heat of water = 4.2 J/g.°C

ΔT = (final temperature) - (Initial temperature)

<pAccording to the graph,

Final water temperature = 25°C

Initial water temperature = 22°C

ΔT = 25 - 22 = 3°C

Q = (2000×4.2×3) = 25,200 J = 25.2 kJ

Hope this Helps!!!

6 0
2 months ago
A chemist combined chloroform (CHCl3) and acetone (C3H6O) to create a solution where the mole fraction of chloroform is 0.187. T
KiRa [2933]

Answer:

\large \boxed{\text{c = 2.50 mol/L; b = 3.96 mol/kg }}

Explanation:

1. Molar concentration

Designate chloroform as C and acetone as A.

The molar concentration for C is derived from Moles of C per Litres of solution.

(a) Moles of C

We are assuming there are 0.187 moles of C.

This resolves that step.

(b) Litres of solution

Next, identify 0.813 moles of A.

(i) Mass of each component

\text{Mass of C} = \text{0.187 mol C} \times \dfrac{\text{119.38 g C}}{\text{1 mol C}} = \text{22.32 g C}\\\\\text{Mass of A} = \text{0.813 mol A} \times \dfrac{\text{58.08 g A}}{\text{1 mol A}} = \text{47.22 g A}

(ii) Volume of each component

\text{Vol. of C} = \text{22.32 g C} \times \dfrac{\text{1 mL C}}{\text{1.48 g C}} = \text{15.08 mL C}\\\\\text{Vol. of A} = \text{47.22 g A} \times \dfrac{\text{1 mL A}}{\text{0.791 g A}} = \text{59.70 mL A}

(iii) Volume of solution

Assuming mixing doesn't alter the total volume.

V = 15.08 mL + 59.70 mL = 74.78 mL

(c) Molar concentration of C

c = \dfrac{\text{0.187 mol}}{\text{0.07478 L}} = \textbf{2.50 mol/L }\\\\\text{ The molar concentration of chloroform is $\large \boxed{\textbf{2.50 mol/L}}$}

2. Molal concentration of C

Molal concentration is calculated as moles of solute per kilograms of solvent.

Total moles of C = 0.187 mol.

Mass of A = 47.22 g = 0.047 22 kg.

\text{b} = \dfrac{\text{0.187 mol}}{\text{0.047 22 kg}} = \textbf{3.96 mol/kg }\\\\\text{The molal concentration of chloroform is $\large \boxed{\textbf{3.96 mol/kg}}$}

4 0
2 months ago
When a heavy football player and a light one run into each other, which player hits the other with
Anarel [2989]

A heavier player collides with a lighter player using greater force.

The lighter player sustains more injuries following the impact.

Explanation:

A heavier player impacts a lighter player with greater intensity, resulting in more pronounced injuries to the lighter player post-collision.

Force is defined as mass multiplied by the acceleration of an object;

    Force = mass x acceleration

We observe that as mass and acceleration increase, the force exerted rises accordingly.

Clearly, the heavier player's mass surpasses that of the lighter player, leading to a greater force exerted upon collision.

Moreover, the lighter player is likely to be injured more severely after the clash. The momentum generated by the heavier player during the impact is considerably significant. Once they collide, the lighter player will certainly alter their speed and trajectory.

Learn more:

Momentum

5 0
3 months ago
Calculate the mass, in grams, of a single tellurium atom (mte = 127.60 amu ).
castortr0y [3046]

1 atomic mass unit (amu) represents the mass of an atom or is used to measure mass on an atomic scale. It is also referred to as a dalton, abbreviated as Da, while atomic mass unit is indicated as amu.

1 amu can be translated into grams as follows:

1 amu = 1.6 * 10^-2^4 g

Mass of Te = 127.6 amu

For conversion into grams:

M = (127.6 ) * 1.6 * 10^-2^4 g

M = 204.16 * 10^-2^4 g

Therefore, the mass of Te is 204.16 * 10^-2^4 g

8 0
2 months ago
Read 2 more answers
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