Answer:
C. connecting an active metal to designate the pipe as the cathode in an electrochemical cell.
Explanation:
Cathodic protection involves a method to manage the accelerated corrosion of a metal surface by designating it as the cathode within an electrochemical cell. This is accomplished by attaching the protected metal to a more sacrificial metal, which acts as the anode.
This method helps to preserve the metal by introducing a highly reactive metal that serves as the anode, supplying free electrons. By adding these free electrons, the active metal gives up its ions, protecting the less reactive steel from corrosion.
3 first significant figure
6 second significant figure
5 third significant figure
4 cannot exceed 5, so retain 5 instead of increasing it to 6
0.0365
Answer:
The configurations are illustrated below.
Explanation:
Hydrogen possesses a single electron in its outer shell, carbon has 4, nitrogen has 5, and oxygen holds 6. To achieve an octet (or duet for hydrogen), they require 1, 4, 3, and 2 electrons respectively.
Therefore, each hydrogen atom will share one electron with carbon, while the remaining electron will be shared with nitrogen, maintaining 4 electrons available for sharing. Carbon can form two bonds with both oxygen atoms, expanding its octet; however, this renders it unstable, leading to the formation of resonance structures (redistribution of electrons), and charge formation. One of the oxygen atoms will share only one electron with nitrogen.
The two structures are depicted below.
Answer:
Explanation:
In a desert cave, an artifact has been discovered. The anthropologists investigating this artifact want to determine its age. They note that the current activity level of the artifact is 9.25 decays/s, and the carbon mass present is 0.100 kg. To ascertain the artifact's age, they will employ specific constants:
r=1.2
The formula for carbon 14 activity is
where,
is the initial activity of the substance
Now, solve for t
since,
Thus, the age of the artifact is
to two significant figures = 6300 years
Let's represent molecules with symbols as follows:
C₂O₄ = X
and
H₂O = Y
Then,
K [ Co (X)₂ (Y)₂ ]
Since Potassium (K) has an oxidation number of +1
To achieve neutrality, the oxidation number of the coordination sphere needs to equal -1.
Thus,
[ Co (X)₂ (Y)₂ ] = -1
Given that,
the O.N of X is -2
Therefore,
O.N of (X)₂ equals -4
Additionally,
O.N of H₂O is zero since it remains neutral. Therefore,
[Co - 4 + 0 ] = -1
Or,
Co = -1 + 4
Co = +3
Conclusion:
The oxidation number for the coordination sphere is -1, and the oxidation state of copper is +3.
