Response:
It is inferred that the authors of the sonnets belong to a certain poet from the Elizabethan era.
Step-by-step breakdown:
The details provided in the question are as follows:
Population mean, μ = 8.9
Sample mean,
= 10.2
Sample size, n = 6
Alpha, α = 0.05
Population standard deviation, σ = 2.5
Initially, we formulate the null hypothesis and the alternative hypothesis
To conduct this test, we utilize the One-tailed z test.
a) Equation:
By substituting in all relevant values, we determine:
Next,
b) The p-value is computed using the z-table.
P-value = 0.1003
The p-value surpasses the alpha of 0.05
c) Because the p-value exceeds the alpha threshold, there is insufficient evidence to dismiss the null hypothesis, thereby supporting the null hypothesis.
Consequently, it is concluded that the authorship of the sonnets belongs to a particular Elizabethan poet.
5400000, since the 7 rounds the 8 up to 4.
Correct question:
An urn holds 3 red and 7 black balls. Players A and B take turns withdrawing balls until a red one is chosen. Calculate the probability that A picks the red ball. (A goes first, followed by B, with no replacement of drawn balls).
Answer:
The likelihood that A picks the red ball is 58.33 %
Step-by-step explanation:
A will select the red ball if it is drawn 1st, 3rd, 5th, or 7th.
1st draw: 9C2
3rd draw: 7C2
5th draw: 5C2
7th draw: 3C2
Calculating for all possible scenarios gives us:
9C2 = (9!) / (7!2!) = 36
7C2 = (7!) / (5!2!) = 21
5C2 = (5!) / (3!2!) = 10
3C2 = (3!) / (2!) = 3
Adding these possibilities results in 36 + 21 + 10 + 3 = 70.
The total outcomes for selecting a red ball = 10C3
10C3 = (10!) / (7!3!)
= 120.
The probability that A selects the red ball is determined by dividing the sum of possible events by the overall outcomes.
P( A selects the red ball) = 70 / 120
= 0.5833
= 58.33 %
In the seventh-grade data, the left side appears similar to the right side, unlike in the fifth-grade data. In seventh grade, we can divide the dots into two equal segments, one ranging from 0 to 3 and the other from 4 to 7. The distribution in the first segment is {2, 2, 3, 5}, while the second segment has {5, 3, 3, 1}. These sides mirror each other. When attempting a comparable division in the fifth-grade data, we find one segment from 1 to 4 with a distribution of {2, 3, 1, 4}, and another from 5 to 8 with a distribution of {5, 5, 2, 2}. In this case, the left side does not reflect the right side, indicating a lack of symmetry.
Shane and Abha received a team badge for gathering at least 2000 cans for recycling.
This indicates that their collection must total a minimum of 2000 cans.
Abha managed to collect 178 more cans than Shane.
Let’s denote the number of cans Shane collected as S
So, Abha collected = S + 178
The inequality representing the number of cans collected by Shane can be expressed as:

=


