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shusha
15 days ago
13

Air is compressed adiabatically from p1 1 bar, T1 300 K to p2 15 bar, v2 0.1227 m3 /kg. The air is then cooled at constant volum

e to T3 300 K. Assuming ideal gas behavior, and ignoring kinetic and potential energy effects, calculate the work for the first process and the heat transfer for the second process, each in kJ per kg of air. Solve the problem each of two ways:
Engineering
1 answer:
pantera1 [230]15 days ago
7 0
Work done during the adiabatic process equals -247873.6 J/kg or -247.9 kJ/kg, while the heat transferred during the constant volume process amounts to -244.91 kJ/kg. Starting from the initial state, we have P₁ = 1 bar (10⁵ Pa), and T₁ = 300 K. The second state has P₂ = 15 bar (15 × 10⁵ Pa) with V₂ = 0.1227 m³/kg. The third state is at P₃ =?, T₃ = 300 K. To find the work done for step 1-2 (the adiabatic process), we also require the heat exchanged during step 2-3 (constant volume). The formula for work in an adiabatic process includes the specific heat ratio γ, which for air is 1.4. The constant K can be found using the second state parameters. Additional calculations will yield the necessary values.
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An AM radio transmitter operating at 3.9 MHz is modulated by frequencies up to 4 kHz. What are the maximum upper and lower side
Mrrafil [271]

Answer:

Total bandwidth: 8 kHz

Explanation:

Data provided:

Transmitter frequency: 3.9 MHz

Modulation up to: 4 kHz

Solution:

For the upper side frequencies:

Upper side frequencies = 3.9 × 10^{6} + 4 × 10³

Upper side frequencies = 3.904 MHz

For the lower side frequencies:

Lower side frequencies = 3.9 × 10^{6} - 4 × 10³

Lower side frequencies = 3.896 MHz

Consequently, the total bandwidth is computed as:

Total bandwidth = upper side frequencies - lower side frequencies

Total bandwidth = 8 kHz

6 0
21 day ago
Write cout statements with stream manipulators that perform the following:
grin007 [242]

Answer:

A)cout<<setw(9)<<fixed<<setprecision(2)<<34.789;

B)cout<<setw(5)<<fixed<<setprecision(3)<<7.0;

C)cout<<fixed<<5.789E12;

D)cout<<left<<setw(7)<<67;

Explanation:

Stream Manipulators are special functions for use with the insertion (<<) and extraction (>>) operators on C++ stream objects, while the 'cout' statement outputs content to the standard output device in C++ programming.

setw: specifies the minimum width of the output field

setprecision: defines the number of decimal places for floating-point value formatting.

fixed: sets the format flag for floating-point streams.

left: left-aligns the output.

A) This statement shows the number 34.789 in a field that provides eight character spaces with two decimal precision. cout<<setw(9)<<fixed<<setprecision(2)<<34.789;

B) Here, the number 7.0 is displayed within six spaces with three decimal precision. cout<<setw(5)<<fixed<<setprecision(3)<<7.0;

C) This command prints 5.789e+12 in fixed-point format.  cout<<fixed<<5.789E12;

D) This statement left-aligns the number 67 across a field of six spaces. cout<<left<<setw(7)<<67;

7 0
25 days ago
The rigid beam is supported by a pin at C and an A992 steel guy wire AB of length 6 ft. If the wire has a diameter of 0.2 in., d
Mrrafil [271]

Answer:

Change in length = 0.0913 in

Explanation:

Given data:

Length = 6 ft

Diameter = 0.2 in

Load w = 200 lb/ft

Solution:

We start by applying the equilibrium moment about point C, expressed as

∑M(c) = 0.............1

This can be used to find the force in AB.

10× 200 × ( 5) - (T cos(30)) × 10 = 0

Solving gives us

Tension in wire T(AB) = 1154.7 lb

We also know the modulus of elasticity for A992 is

E = 29000 ksi

And the area will be

Area = \frac{\pi }{4}\times 0.2^2

The change in length is expressed as

Change in length = \frac{PL}{AE}.........2

Substituting values results in

Change in length = \frac{1154.7 \times 6 \times 12}{\frac{\pi }{4}\times 0.2^2 \times 29000 \times 1000}

Change in length = 0.0913 in

8 0
28 days ago
How does Accenture generate value for clients through Agile and DevOps?
Daniel [248]
By securing stakeholder needs throughout the project planning stage via thorough process documentation that is revised after each work cycle.
7 0
1 month ago
Read 2 more answers
3/63 A 2‐kg sphere S is being moved in a vertical plane by a robotic arm. When the angle θ is 30°, the angular velocity of the a
Kisachek [244]

Answer:

Ps=19.62N

Explanation:

A thorough explanation of the answer can be found in the attached files.

5 0
1 month ago
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