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kompoz
2 months ago
14

3/63 A 2‐kg sphere S is being moved in a vertical plane by a robotic arm. When the angle θ is 30°, the angular velocity of the a

rm about a horizontal axis through O is 50 deg/s clockwise and its angular acceleration is 200 deg/s2 counterclockwise. In addition, the hydraulic element is being shortened at the constant rate of 500 mm/s. Determine the necessary minimum gripping force P if the coefficient of static friction between the sphere and the gripping surfaces is 0.50. Compare P with the minimum gripping force Ps required to hold the sphere in static equilibrium in the 30° position.

Engineering
1 answer:
Kisachek [356]2 months ago
5 0

Answer:

Ps=19.62N

Explanation:

A thorough explanation of the answer can be found in the attached files.

You might be interested in
Consider 1.0 kg of austenite containing 1.15 wt% C, cooled to below 727C (1341F). (a) What is the proeutectoid phase? (b) How
pantera1 [306]

Answer:

a) The phase before eutectoid is commonly referred to as cementite, with the chemical formula Fe₃C.

b) The total mass of ferrite obtained is 0.8311 kg.

The total cementite mass equals 0.1689 kg.

c) The total cementite mass accounts for 0.9343 kg.

Explanation:

Provided:

1 kg of austenite

a carbon content of 1.15 wt%

Cooled below 727°C

Questions:

a) Identify the proeutectoid phase.

b) Calculate the mass of total ferrite and cementite, Wf =?, Wc =?

c) Determine the mass of both pearlite and the proeutectoid phase, Wp =?

d) Create a schematic to illustrate the resulting microstructure.

a) The proeutectoid phase is referred to as cementite with the formula Fe₃C.

b) To find the total mass of formed ferrite:

W_{f} =\frac{C_{cementite}-C_{2} }{C_{cementite}-C_{1} }

With:

Ccementite = composition of cementite = 6.7 wt%

C₁ = composition of phase 1 = 0.022 wt%

C₂ = overall composition = 1.15 wt%

Inserting the values yields:

W_{f} =\frac{6.7-1.15}{6.7-0.022} =0.8311kg

For the total mass of cementite:

W_{c} =\frac{C_{2}-C_{1}}{C_{cementite}-C_{1} } =\frac{1.15-0.022}{6.7-0.022} =0.1689kg

c) The mass of pearlite:

W_{p} =\frac{6.7-1.15}{5.94} =0.9343kg

d) The diagram illustrates the different compositions: (pearlite, proeutectoid cementite, ferrite, eutectoid cementite)

6 0
3 months ago
A well-insulated rigid tank contains 1.5 kg of a saturated liquid–vapor mixture of water at 200 kPa. Initially, three-quarters o
Daniel [329]

Answer:

The change in entropy of the steam is 2.673 kJ/K

Explanation:

The mass of the liquid-vapor mixture is 1.5 kg

The mass in the liquid phase is calculated as 3/4 × 1.5 kg = 1.125 kg

The mass in the vapor phase is calculated as 1.5 - 1.125 = 0.375 kg

According to the steam tables

At a pressure of 200 kPa (200/100 = 2 bar), the specific entropy of steam is found to be 7.127 kJ/kgK

The entropy of steam can be calculated as specific entropy multiplied by mass = 7.127 × 0.375 = 2.673 kJ/K

6 0
2 months ago
Read 2 more answers
6. You are evaluating flow through an airway. The current flow rate is 10 liters per minute with a fixed driving pressure (P1) o
iogann1982 [368]

Answer:

B) P1 would have to increase to sustain the flow rate (correct)

C) Resistance would rise (correct)

Explanation:

Flow rate is measured at 10 liters per minute

Driving pressure (P1) stands at 20 cm H2O

Fixed downstream pressure (P2) is 5 cm H2O

The accurate statements when the lumen is pinched in the center of the tube are: P1 will increase to maintain the flow rate, and resistance will rise. This occurs because pinching the lumen decreases its diameter, leading to higher resistance, which is linearly related to pressure, thus P1 will also increase.

The incorrect statement is: the flow would decrease.

6 0
2 months ago
Suppose we include the lead resistance in the calculation of temperature for a class A RTD. If R3 = 1000 ohms, Ra = 18 ohms, V0
alex41 [359]

Respuesta:

La temperatura máxima que se puede medir (en °C) es 14170.27°C

Explicación:

Los RTDs son termómetros compuestos de metales cuya resistencia aumenta con la temperatura.

Para un RTD de Clase A, l, Alpha = 0.00385.

La fórmula para el RTD es

Rt = Ro ( 1 + alpha x t)

Donde

Rt es la resistencia a la temperatura t°C,

Ro es la resistencia a 0°C

Alpha es un coeficiente de temperatura constante para un RTD de clase A.

Aquí, Rt = 1000ohms,

Ro se considera como Ra = 18Ohms

Por lo tanto,

1000 = 18 ( 1 + 0.00385t)

Dividiendo ambos lados por 18

1 + 0.00385t = 1000/18

0.00385t = 55.55 - 1

0.00385t = 54.55

t = 54.55/0.00385

t = 14170.27°C

5 0
1 month ago
Three return steam lines in a chemical processing plant enter a collection tank operating at steady state at 1 bar. Steam enters
alex41 [359]

Response:

a) 4 kg/s

b) 99.61 °C

Rationale:

Refer to the pictures provided.

5 0
1 month ago
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